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liq [111]
3 years ago
7

Write the slope intercept form of each line.

Mathematics
2 answers:
Solnce55 [7]3 years ago
7 0

Answer:

8

Step-by-step explanation:

Kaylis [27]3 years ago
6 0
Answer is 8, This is side in line?
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Get to me when can. THANKS!!!
lawyer [7]

Answer:56

Step-by-step explanation:

50 - 23 + 29 = 56

4 0
3 years ago
Which expression represents the inverse of y = 12x - 3
a_sh-v [17]
<span>y = x + 3 / 12
This is your answer.</span>
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3 years ago
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What is the solution to the inequality a-3&gt;5
Lady bird [3.3K]

Answer:

a > 8

Step-by-step explanation:

a-3>5

Add 3 to each side

a-3+3>5+3

a > 8

6 0
3 years ago
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Given: Triangle ABC : triangle ADB. AB =24, AD =16 <br> Find: AC
RoseWind [281]

Answer:

<h2>AC = 36.01</h2>

Step-by-step explanation:

Given ΔABC and ΔADB, since both triangles are right angled triangles then the following are true.

From ΔADB, AB² = AD²+BD²

Given AB = 24 and AD = 16

BD² = AB² - AD²

BD² = 24²-16²

BD² = 576-256

BD² = 320

BD = \sqrt{320}

BD = 17.9

from ΔABC, AC² = AB²+BC²

SInce AC = AD+DC and BC² = BD² + DC² (from ΔBDC )we will have;

(AD+DC)² = AB²+ (BD² + DC²)

Given AD = 16, AB = 24 and BD = 17.9, on substituting

(16+DC)² = 24²+17.9²+ DC²

256+32DC+DC² =  24²+17.9²+ DC²

256+32DC = 24²+17.9²

32DC = 24²+17.9² - 256

32DC = 640.41

DC = \frac{640.41}{32}

DC = 20.01

Remember that AC = AD+DC

AC = 16+20.01

AC = 36.01

6 0
3 years ago
Mitch works at Comedy Cinema's concession stand. He has
Stells [14]

Answer:

Step-by-step explanation:

Students use algebra to solve equations (of the form px + q = r and p(x + q) = r where p, q, and r are specific rational numbers); using techniques of making zero (adding the additive inverse) and making one (multiplying by the multiplicative inverse) to solve for the variable.

Students identify and compare the sequence of operations used to find the solution to an equation algebraically, with the sequence of operations used to solve the equation with tape diagrams. They recognize the steps as being the same.

Students solve equations for the value of the variable using inverse operations; by making zero (adding the additive inverse) and making one (multiplying by the multiplicative inverse).

8 0
3 years ago
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