Answer:
...
Step-by-step explanation:
since they give us the side opposite of the given angle(Opposite) and we are trying to find for a (Adjacent/side), so we use TOA
tan(30)= ![\frac{4}{a}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7Ba%7D)
i see u dont want it solved but ill solve it anyways
since a is on the bottom then lets switch them
![x=\frac{4}{tan30}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B4%7D%7Btan30%7D)
x= 6.928
Answer:
The answer is 63.5 feet :)
Answer:
The distance between the points is approximately 6.4
Step-by-step explanation:
The given coordinates of the points are;
(2, -2), and (6, 3)
The distance between two points, 'A', and 'B', on the coordinate plane given their coordinates, (x₁, y₁), and (x₂, y₂) can be found using following formula;
![l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}](https://tex.z-dn.net/?f=l%20%3D%20%5Csqrt%7B%5Cleft%20%28y_%7B2%7D-y_%7B1%7D%20%20%5Cright%20%29%5E%7B2%7D%2B%5Cleft%20%28x_%7B2%7D-x_%7B1%7D%20%20%5Cright%20%29%5E%7B2%7D%7D)
Substituting the known 'x', and 'y', values for the coordinates of the points, we have;
![l_{(2, \, -2), \ (6, \, 3) } = \sqrt{\left (3-(-2) \right )^{2}+\left (6-2 \right )^{2}} = \sqrt{5^2 + 4^2} = \sqrt{41}](https://tex.z-dn.net/?f=l_%7B%282%2C%20%5C%2C%20-2%29%2C%20%5C%20%286%2C%20%5C%2C%203%29%20%7D%20%3D%20%5Csqrt%7B%5Cleft%20%283-%28-2%29%20%20%5Cright%20%29%5E%7B2%7D%2B%5Cleft%20%286-2%20%20%5Cright%20%29%5E%7B2%7D%7D%20%3D%20%5Csqrt%7B5%5E2%20%2B%204%5E2%7D%20%3D%20%5Csqrt%7B41%7D)
Therefore, the distance between the points, (2, -2), and (6, 3) = √(41) ≈ 6.4.
Add 4/5 and 1/5 to make 5/5 or 1 mile the subtract 1 from 2 1/2 to equal 1 1/2 miles