All categories

4 years ago

What is the area, in square centimeters, of the figure below? 2.4cm, 5.8cm

Mathematics

1 answer:

nirvana33 [79]4 years ago

8 0

Answer:

13.92

Step-by-step explanation:

You might be interested in

What is the estimate of 15 ÷ 485

leva [86]

i think it 30 but I could be wrong

4 0

3 years ago

29,17,38,71,35,63,24. Two numbers that add up to 100. Two numbers which differ by 46, a multiple of 9

Dmitry [639]

2 numbers that add up to 100: 71+29=100

2 numbers which differ by 46: 63-17=46

A multiple of 9: 9x7=63

8 0

3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPp

love history [14]

Answer:

36 in²

Step-by-step explanation:

Area of the figure

Area (small rectangle) left + Area (big rectangle) right
3 x (6 - 4) + 5 x 6
3 x 2 + 30
6 + 30
36 in²

3 0

3 years ago

Read 2 more answers

Biggest tree in the world:

AnnZ [28]

Answer:

80m

Step-by-step explanation:

The height of giant redwood tree is 100m.

so half of it is 50m

The height of redwood tree is 30m+ 50m= 80m

5 0

3 years ago

Read 2 more answers

AABC has vertices at A(1, -9), B(8,0), and C(9,-8).

Rainbow [258]

Check the picture below.

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{-9})\qquad B(\stackrel{x_2}{8}~,~\stackrel{y_2}{0}) ~\hfill AB=\sqrt{[ 8- 1]^2 + [ 0- (-9)]^2} \\\\\\ AB=\sqrt{7^2+(0+9)^2}\implies AB=\sqrt{7^2+9^2}\implies \boxed{AB=\sqrt{130}} \\\\[-0.35em] ~\dotfill$

$B(\stackrel{x_1}{8}~,~\stackrel{y_1}{0})\qquad C(\stackrel{x_2}{9}~,~\stackrel{y_2}{-8}) ~\hfill BC=\sqrt{[ 9- 8]^2 + [ -8- 0]^2} \\\\\\ BC=\sqrt{1^2+(-8)^2}\implies \boxed{BC=\sqrt{65}}$

now, we could check for the CA distance, however, we already know that AB ≠ BC, so there's no need.

6 0

3 years ago