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Aleks04 [339]
3 years ago
6

Under which conditions would the limit as x approaches 7 not exist? Check all that apply.

Mathematics
2 answers:
hammer [34]3 years ago
8 0

Answer:

1,2, & 5

Step-by-step explanation:

edge 2021

Evgen [1.6K]3 years ago
3 0

(I've done this assigment so here are all the answers.)

Answer :

Q1. f'(x)=-20x+4. When x=11, this is f'(11)=-20×11+4=-220+4=-216.

Q2. Lim(x➝4) of x²+3x-1. The expression can be evaluated by direct substitution without constraints: 16+12-1=27.

Q3. The derivative is 7 for all values of x because the function is linear with a constant slope.

Q4. The function is piecewise. We need the conditions that apply when x is close to zero. We need to look at x approaching from the negative side and the positive side. If the limits are not the same the limit does not exist. So, when x<0 we use 7-x². When x is just less than zero, this left-hand limit is 7. When x>0 we use 10x+7. When x is just bigger than zero, this right-hand limit is 7. We are not interested in x=0, we are only interested in the left- and right-hand limits, which happen to be the same. So the limit is 7.

Q5. f'(x)=-3/x². f'(1)=-3.

Q6.  In all limit questions, you can always ignore what happens when x=limit, because it’s the approaches that matter. So x➝2⁻ means look at the graph on the left of the limit. The horizontal line at y=4 means the left limit is 4. x➝2⁺ means look at the graph on the right of the limit. This is where y=-3, so the right limit is -3. The answer is 4 and -3 for left and right limits respectively.

Q7. First find left and right limits: x➝-1⁻: use x<-1: f(x)=x+1, so left limit is 0; x➝-1⁺: use x>-1: f(x)=1-x: so right limit is 1-(-1)=2. The left and right limits are different, so the limit does not exist.

Q8. 1/(x-7). When x=7, this quantity is not defined and this is a vertical asymptote. When x➝7⁻ we can use a value of x slightly less than 7 and see what happens. First try x=6.99, then 1/(x-7)=-100. Now try x=6.999, then we get -1000. So it’s getting larger in magnitude, and it’s negative. An infinitely large negative value is -∞. So the limit as x approaches 7 from the left is -∞.

Q9. Ignore the closed point at (3,7). For x➝3⁻, we are on the sloping line, so the limit is 1.5.

Q10. As x approaches zero the numerator approaches 1. The denominator gets smaller so its reciprocal gets larger, and it can be positive or negative depending on how we approach zero. So we can’t define the limit, so it doesn’t exist.

Q11. Derivative is -(-3/x²)=3/x². When x=-4, this is 3/16, because (-4)²=16.

Q12. x²-2➝-2 when x➝0.

Q13. (x²-16)/(x-4)=(x-4)(x+4)/(x-4)➝x+4 because the common factor x-4 cancels. Note that the quantity does not exist at precisely x=4 but in the limit it approaches x+4=8 when x=4. So the answer is 8 for the limit.

Q14. The derivative is constant -13 and is independent of t, so the instantaneous velocity is -13.

Q15. 1/(x-2)² is always positive, so it doesn’t matter whether we look at the left or right limits. The result as x➝2 is ∞, which is an undefinable quantity. x=2 is a vertical asymptote.

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A box of oat cereal costs $3.90 for 15 ounces. A box of rice of cereal costs $3.30 for 11 ounces. Which box of cereal costs less
Firlakuza [10]

Answer:

The cost of per ounce of oat cereal is $0.04 less than per ounce cost of rice.

Step-by-step explanation:

Given:

Cost of 15 ounces of oat cereal box = $3.90

Cost of 11 ounces of rice box = $3.30

To compare the unit prices of the the boxes.

Solution:

Using unitary method to find the unit prices:

If 15 ounce of oat box cost =$3.90

∴ 1 ounce of oat cereal would cost = \$\frac{3.90}{15}=\$0.26

∴ Per ounce cost of oat cereal = $0.26

If 11 ounce of rice box cost =$3.30

∴ 1 ounce of rice would cost = \$\frac{3.30}{11}=\$0.3

∴ Per ounce cost of rice = $0.3

Difference in unit costs of oat and rice = \$0.3-\$0.26=\$0.04

On comparing the the unit costs of oats and rice, we find out that the cost of per ounce of oat cereal is $0.04 less than per ounce cost of rice.

3 0
3 years ago
Tuesday and Wednesday work
AURORKA [14]
Prime factorizations - Wednesday work
1. 44     2^2 • 11
2. 125    5^3
3. 85     5 • 17
4. 39     3 • 13
5. 63     3^2 • 7
6. 240    2^4 • 3 • 5
7. 87     3 • 29
8. 45     3^2 • 5
8 0
3 years ago
Sean chewed 2/5 of his rawhide bones. If he had 10 bones to begin with, how many did he chew up?
Vesna [10]

Answer:

He chewed 4/10 of the bone

Step-by-step explanation:

Since the 10 will be the denominator you will need to divide it by 2 and get 5. After that you multiply the denominator of 10 and numerator of 1 by 2 and get 4/10

4 0
3 years ago
9. Evaluate (-7) -10 ÷ (-28)-10<br> pls solve fast
Juli2301 [7.4K]

Answer:

17/38 or ≈ 0.45

Step-by-step explanation:

(-7) -10 / (-28)-10

= -17 / -38

= 17/38

You can keep the answer in fraction as 17/38 or ≈ 0.45

Hope this help you :3

7 0
3 years ago
PLSSS HELP GIVING BRAINLIEST
mylen [45]

Answer: 180

Step-by-step explanation:

8 0
2 years ago
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