Question

Write the equation in logarithmic form.

Answer 1

Answer:

The answer is C. $log_2(32)=5$

Step-by-step explanation:

The logarithmic form is:

$log_b(x)=y\\b^y=x$

Where:

b is the base of the logarithmic.

In this case, the base could be "2" because the left side of the equation has a 2 powered by 5 and the right side of the equation has a 32 that is equal to 2 powered by 6. Also we can apply the next property:

$log(a^b)=b*log(a)$

So, we have to reverse the form from exponential to logarithmic.

Then:

$2^5=32\\log_2(2^5)=log_2(32)\\5*log_2(2)=log_2(32)\\5*1=log_2(32)\\log_2(32)=5$

Finally, the equation in logarithmic form is C. $log_2(32)=5$

Answer 2

An equation with the form $b^x=y$ has a logarithmic form of $log_b(y) = x.$. The logarithmic form of $2^5=32$ where in b = 2, x=5, and y=32 is
$log_232=5$.