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NARA [144]
3 years ago
14

A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data greater tha

n 6.9.
about 16 %

about 34%

about 13.5%

about 2.5%
Mathematics
1 answer:
ankoles [38]3 years ago
6 0
P(x > 6.9) = 1 - P(x < 6.9) = 1 - P[z < (6.9 - 5.1)/0.9] = 1 - P(z < 2) = 1 - 0.97725 = 0.02275.

Therefore P(x > 6) is about 2.5%
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Kennedy is making chicken noodle soup for her little brothers she has three cans that have a radius of 2 inches in height of 6 i
lozanna [386]

Answer:

226.08 in^3

Step-by-step explanation:

volume of a cylinder = nr^2h

3.14 x 2^2 x 6 = 75.36 in^3

75.36 x 3 = 226.08

3 0
3 years ago
A fraction with a numerator that is greater than or equal to the denominator is an
GarryVolchara [31]
****Equal to one or greater than 1***
3 0
3 years ago
50. Insert three geometric means between 2 and 512.
saveliy_v [14]
The three geometric means between 3 and 512 are…


8, 32, 128

OR

-8, 32, -128
5 0
2 years ago
Farmer Company purchased equipment on January 1, Year 1 for $82,000. The equipment is estimated to have a 5-year life and a salv
aalyn [17]

Answer:

option (a) $6,240

Step-by-step explanation:

Given:

Purchasing cost of the equipment = $82,000

Estimated life = 5 years

Salvage value = $4,000

Revised expected life = 8 years

Now,

Depreciation per year = \frac{\textup{82,000-4,000}}{\textup{5}}

therefore,

The accumulated Depreciation at the beginning of year 4

= Annual depreciation × years passed

= 15,600 × 3

= $46,800

Thus,

The book value at the beginning of year 4

= Purchasing cost - Depreciation

= $82,000 - $46,800

= $35,200

Now,

The remaining life = Revised estimated life - Years passed

= 8 - 3

= 5 years

therefore,

Depreciation expense =\frac{\textup{book value at the beginning of year 4 - salvage value}}{\textup{Revised estimated life}}

= \frac{\textup{35,200  - 4000}}{\textup{5}}

= $6,240

Hence,

The correct answer is option (a) $6,240

7 0
3 years ago
Complete the paragraph proof. We are given that ∠B ≅ ∠C. Assume segment AB is not congruent to . If AB &gt; AC, then m∠C &gt; m∠
Lorico [155]

Given that ∠B ≅ ∠C.

to prove that the sides AB = AC

This can be done by the method of contradiction.  

If possible let AB \neq=AC

Then either AB>AC or AB<AC

Case i:  If AB>AC, then by triangle axiom, Angle C > angle B.

But since angle C = angle B, we get AB cannot be greater than AC

Case ii:  If AB<AC, then by triangle axiom, Angle C < angle B.

But since angle C = angle B, we get AB cannot be less than AC

Conclusion:

Since AB cannot be greater than AC nor less than AC, we have only one possibility. that is AB =AC

Hence if angle B = angle C it follows that

AB = AC, and AB ≅ AC.

6 0
3 years ago
Read 2 more answers
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