Answer:
The 80% confidence interval for the population mean is between 28.32 characters and 31.68 characters.
Step-by-step explanation:
We have the standard deviation for the population, so we can use the normal distribution. If we had the standard deviation for the sample, we would have to use the t-distribution.
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 30 - 1.68 = 28.32 characters.
The upper end of the interval is the sample mean added to M. So it is 30 + 1.68 = 31.68 characters.
The 80% confidence interval for the population mean is between 28.32 characters and 31.68 characters.
Without knowing the gradient you will only be able to get as far as y=mx+5
8/x = 2/5
cross multiply
(2)(x) = (8)(5)
2x = 40
x = 40/2
x = 20
now check out ur fractions : 8/20 = 2/5....notice that they are equivalent fractions...just like proportions...nothing but equivalent fractions
Answer: The probability that 3 or more of the next 5 customers will order chocolate is 30%. 3/10
Sandy conducted her own experiment to answer this question. She observed what groups of 5 customers ordered. In her experiment, 30% of the time at least 3 of the customers ordered chocolate.
The fraction 30% is 3/10.