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Sindrei [870]
4 years ago
5

The temperature was 8°f. It dropped so that the temperature was 0°f. What integer represents the change in temperature?

Mathematics
1 answer:
Gnoma [55]4 years ago
3 0
Positive 8 or just 8
You might be interested in
Expand the following:<br> a.x(x+5)<br> b.x(3x-1)<br> c.2x(2x+3)<br> d.5x(x-3y)
trasher [3.6K]
It would A because that’s obviously the right answer.
8 0
3 years ago
1140 was rounded to the nearest ten.<br>What is the upper bound?<br>​
zloy xaker [14]

Answer:

1145

Step-by-step explanation:

  • <em>The upper bound is the smallest value that would round up to the next estimated value</em>.

Since the number was rounded to nearest ten, the upper bound is:

  • 1145

which rounds up to 1150 which is the next estimated value greater than 1140

8 0
3 years ago
Read 2 more answers
Which of the following sets are subspaces of R3 ?
Ratling [72]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

\to A={(x,y,z)|3x+8y-5z=2} \\\\\to  for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

                                        =3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)

The set A is not part of the subspace R^3

for point B:

\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon  B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)

                                             =-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0

\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon  B

The set B is part of the subspace R^3

for point C: \to C={(x,y,z)|x

In this, the scalar multiplication can't behold

\to for (-2,-1,2) \varepsilon  C

\to -1(-2,-1,2)= (2,1,-1) ∉ C

this inequality is not hold

The set C is not a part of the subspace R^3

for point D:

\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)

The scalar multiplication s is not to hold

\to for (-4, 1,2)\varepsilon  D\\\\\to  -1(-4,1,2) = (4,-1,-2) ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace R^3

For point E:

\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to  a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\

The  x_1, x_2 is the arbitrary, in which ax_1+bx_2is arbitrary  

\to a(x_1,0,0)+b(x_2,0,0) \varepsilon  E

The set E is the part of the subspace R^3

For point F:

\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon  F \\\\\to  a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))

The x_1, x_2 arbitrary so, they have ax_1+bx_2 as the arbitrary \to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F

The set F is the subspace of R^3

5 0
3 years ago
Given that tan^2 theta=3/8,what is the value of sec theta?
algol [13]

Answer:

The value of SecФ is  \pm \sqrt{\frac{11}{8}} .

Step-by-step explanation:

Given as for trigonometric function :

tan²Ф = \frac{3}{8}

Or, tanФ = \sqrt{\frac{3}{8} }

∵ tanФ = \frac{Perpendicular}{Base}

So,  \frac{Perpendicular}{Base} =  \sqrt{\frac{3}{8} }

So, Hypotenuse² = perpendicular² + base²

or, Hypotenuse² = ( \sqrt{3} )² + ( \sqrt{8} )²

Or,  Hypotenuse² = 3 + 8 = 11

Or,  Hypotenuse = ( \sqrt{11} )

Now SecФ = \frac{Hypotenuse}{Base}

or, SecФ = \frac{\sqrt{11}}{\sqrt{8}} = \sqrt{\frac{11}{8} }

<u>Second Method</u>

Sec²Ф - tan²Ф = 1

Or, Sec²Ф = 1 +  tan²Ф

or, Sec²Ф = 1 +  \frac{3}{8}

Or, Sec²Ф = \frac{11}{8}

Or,  SecФ = \pm \sqrt{\frac{11}{8}}

Hence The value of SecФ is  \pm \sqrt{\frac{11}{8}} . Answer

7 0
3 years ago
Read 2 more answers
A promoter buys advertising in units of $30,000 each. If he buys two units of broadcast TV, one unit of cable TV, and two units
andriy [413]

Answer:

$150,000

Step-by-step explanation:

The first step is to calculate the total number of units

= 2 +1 +2

= 5

If he buys at the rate of $30,000 for one unit then the total money spent on advertising can be calculated as follows

= 30,000 × 5

= 150,000

Hence the promoter spends $150,000 on advertising

4 0
4 years ago
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