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lutik1710 [3]
4 years ago
6

Can anyone help i don’t know how to do it and it’s GEMDAS not PEMDAS?

Mathematics
2 answers:
Firlakuza [10]4 years ago
5 0

Answer:

GEMDAS rate. (Abbreviation) A mnemonic used to  the order of operations in math problems; Grouping (such as parentheses), Exponents, Multiplication, Division, Addition, Subtraction.

Step-by-step explanation:

its pemdas just with a different name!!

do you still need help?

Maurinko [17]4 years ago
4 0
ItS PEMDAS not GEMDAS bro
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Determine which line the point (2, -1) lies on.
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Answer: the x axis because its positive 2, -1 the first number is positive

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3 years ago
What is the 12<br>th term rule of the linear sequence 13 7 1 -5 -11​
Sergeu [11.5K]

Answer:

<u>-53</u>, f(n) = -6(n-1) + 13

Step-by-step explanation:

given the equation to this linear/arithmetic sequence for the nth term: f(n) = -6(n-1) + 13

f(12) = -6(12-1) + 13

f(12) = -6(11) + 13

f(12) = -66 + 13

f(12) = -53

*substitute and simplify*

______________

f(n) = f(1) + d(n-1)

given f(1) = 13, f(2) = 7, and f(3) = 1

7-13 = 1-7 = <u>-6</u> = d

= f(1) + d(n-1)

f(1) = <u>13</u> so

the equation must be f(n) = <u>13</u> <u>-</u><u> </u><u>6</u>(n-1) or -6(n-1) + 13

3 0
3 years ago
How to divide 90 divided by 15
MakcuM [25]

Answer:

6

Step-by-step explanation:

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3 years ago
Find the solution of 5 times the square root of the quantity of x plus 7 equals negative 10, and determine if it is an extraneou
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5sqrt(x+7)=-10
Dividing both sides by 5:
5sqrt(x+7)/5=-10/5
sqrt(x+7)=-2
Squaring both sides of the equation:
[sqrt(x+7)]^2=(-2)^2
x+7=4
x+7-7=4-7
x=-3

Replacing in the original equation:
5sqrt(x+7)=-10
5sqrt(-3+7)=-10
5sqrt(4)=-10
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3 years ago
Complete the point-slope equation of the line through (-8,-1)(−8,−1)
ZanzabumX [31]

Answer:

The equation of the line is y = -1

Step-by-step explanation:

In order to find the equation,y = mx + c, you have to find the gradient first using the formula :

m =  \frac{y2 - y1}{x2 - x2}

Let (x1,y1) = (-8,-1) & (x2,y2) = (-8,-1),

m = (-1)-(-1)/-8-(-8)

= 0

Now, we have found the gradient, next using the formula, y = mx + c to find the equation :

y = mx + c

Let m=0,

At (-8,-1)

-1 = 0(-8) + c

c = -1

y = -1

6 0
3 years ago
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