5/9 (f – 32) when f = 50

A car travels for 4(t+3) hours at a constant speed of 10(t+3) km/h. If the total distance travelled by the car is 810 km, find t

IceJOKER [234]

Step-by-step explanation:

$\because \: time \times speed = distance \\ \therefore \: 4(t + 3) \times 10(t + 3) = 810 \\ \therefore \: 4(t + 3)^{2} = 81 \\ \therefore \: \{2(t + 3) \}^{2} = {9}^{2} \\ \therefore \: \{2(t + 3) \} = {9} \\ \therefore \: t + 3 = \frac{9}{2} \\ \therefore \: t = \frac{9}{2} - 3 \\ \therefore \: t = \frac{9 - 6}{2} \\ \therefore \: t = \frac{3}{2} \\ \therefore \: t = 1.5 \: hrs \\$

$\because \: time \times speed = distance \\ \therefore \: 4(t + 3) \times 10(t + 3) = 810 \\ \therefore \: 4(t + 3)^{2} = 81 \\ \therefore \: \{2(t + 3) \}^{2} = {9}^{2} \\ \therefore \: \{2(t + 3) \} = {9} \\ \therefore \: t + 3 = \frac{9}{2} \\ \therefore \: t = \frac{9}{2} - 3 \\ \therefore \: t = \frac{9 - 6}{2} \\ \therefore \: t = \frac{3}{2} \\ \therefore \: t = 1.5 \: hrs \\ speed \: of \: car = 10(t + 3) \\ \hspace{60 pt} = 10(1.5 + 3) \\ \hspace{60 pt}= 10 \times 4.5 \\ \red{ \boxed{ \bold{ \therefore \: speed \: of \: car = 45 \:km/ h}}} \\$

3 0

3 years ago

NEED HELP ASAP GIVING BRAINLIST!!!!!

lbvjy [14]

Answer:

Top left: x^2 +8x +15

Top right: x^2 +3x -18

Bottom left: x^2 -3x -18

Bottom right: x^2 -10x +16

Step-by-step explanation:

6 0

2 years ago

The sale price of every item in a store is 75% of its usual price. A. The usual price of a jacket is $80, what is its sale price

riadik2000 [5.3K]

75 × 0.01 = 0.75

0.75 × 80 = $60

75 ×0.01 = 0.75

0.75 × 28 = $21

8 0

2 years ago

Solve for x. What is the solution to the system of equations?<br> ( <br> , <br> )

labwork [276]

(3,-2) hope this helps Yall

5 0

2 years ago

Th the mean of the data is set 15 what number is missing<br> 18,16_,9,12,23

Wittaler [7]

Answer:

The missing number on the given data set is 12.

Step-by-step explanation:

Here, the set of data = 18,16_,9,12,23

Let us assume the missing number in the data = m

The mean of the data = 15

Total number of observations = 6

Now, Sum of the data = 18 + 16 + m + 9+ 12+ 23 = 78 + m

Also, $\textrm{ Mean of the given Data} = \frac{\textrm{Sum of all observation in the data}}{\textrm{Total number of observations}}$

$\implies 15 = \frac{78+ m}{6} \\or, 15(6) = 78 + m\\\implies m = 90 -78 = 12$

or, m = 12

Hence, the missing number on the given data set is 12.

3 0

3 years ago