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aleksklad [387]
3 years ago
8

5/9 (f – 32) when f = 50

Mathematics
2 answers:
kondor19780726 [428]3 years ago
7 0
10

Hope it’s right best luck with your studying
gladu [14]3 years ago
6 0

Answer:

10

Step-by-step explanation:

5/9(50-32)

5/9(18)

5/9×18=10

Hope this helps! :)

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If 7x+4=37, what is the value of 14x-1
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Integral of (3x-2)/(x-1)^2
Goryan [66]
<span><span><span>(3x−2)/</span><span>(x−1<span>)^2</span></span></span>=<span>A/(<span>x−1) </span></span>+ <span><span>B/x</span><span>(x−1<span>)^2
</span></span></span>                       =[<span><span>A(x−1)+Bx</span><span>(x−1<span>)] / 2</span></span></span></span> 3x-2=A(x-1)+Bx
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7 0
3 years ago
The speed of light is approximately 6.71 x 108 miles per hour. Express this number in standard form.
noname [10]

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5 0
3 years ago
Sam paid $8.28 for 18 stamps.at this rate,how much would it cost Sam to buy 12 stamps
allsm [11]

Answer: It costs $5.52 to Sam to buy 12 stamps.


Step-by-step explanation:

Given: Sam paid $8.28 for 18 stamps.

Thus, the cost of 18 stamps = $8.28

Then the cost of 1 stamp=\frac{8.28}{18}

Thus, the cost of 1 stamp=$0.46

With the same rate , the cost of 12 stamps=0.46\times12

Therefore, the cost of 12 stamps= $5.52

hence, it costs $5.52 to Sam to buy 12 stamps.

3 0
3 years ago
Read 2 more answers
How many extraneous solutions does the equation below have? StartFraction 9 Over n squared 1 EndFraction = StartFraction n 3 Ove
BigorU [14]

The equation has one extraneous solution which is n ≈ 2.38450287.

Given that,

The equation;

\dfrac{9}{n^2+1} =\dfrac{n+3}{4}

We have to find,

How many extraneous solutions does the equation?

According to the question,

An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.

To solve the equation cross multiplication process is applied following all the steps given below.

\rm \dfrac{9}{n^2+1} =\dfrac{n+3}{4}\\\\9 (4) = (n+3) (n^2+1)\\\\36 = n(n^2+1) + 3 (n^2+1)\\\\36 = n^3+ n + 3n^2+3\\\\n^3+ n + 3n^2+3 - 36=0\\\\n^3+ 3n^2+n -33=0\\

The roots (zeros) are the  x  values where the graph intersects the x-axis. To find the roots (zeros), replace  y

with  0  and solve for  x. The graph of the equation is attached.

n  ≈  2.38450287

Hence, The equation has one extraneous solution which is n  ≈  2.38450287

For more information refer to the link.

brainly.com/question/15070282

5 0
2 years ago
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