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s344n2d4d5 [400]
3 years ago
6

Grandma's age is 6 years less than 5 times Junior's age, j. If Grandma is 64 years old, which equation

Mathematics
1 answer:
tankabanditka [31]3 years ago
4 0

Answer:

junior is 6

Step-by-step explanation:

take 64 and divide by 5 you get 12 then take away the 6 years and you get juniors age which is 6

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a store had a sale on art supplies. the price p of each item was marked down 60%. which expression represents the new price
andrezito [222]
If the price of the item drops by 60% then that means the new price is 40% of the original

new price = p*0.4

ex: 
new price = $100*0.4= $40
new price= $75*0.4 = $30
5 0
3 years ago
Select the correct answer. For what value of x is sin x = cos 19º, where 0°< x < 90°? OA. 38° ° O B. 71° OC. 26° O D. 19°​
Lerok [7]

Answer:

x = 71°

Option B is correct answer.

Step-by-step explanation:

We need to find for what value of x is sin\: x = cos 19^{\circ}, where 0°< x < 90°?

Solving:

sin\: x = cos\: 19^{\circ}\\Finding \:cos\: 19^{\circ}=0.94551\\Putting\:value:\\sin\:x=0.94551\\Now\:taking\:sin\:inverse\\x=sin^{-1}(0.94551)\\x=71^{\circ}

So, we get x = 71°

Option B is correct answer.

5 0
2 years ago
Graph. y−2=2/3(x+4) Use the Line Tool and select two points to graph the equation. Use the slope and the point provided in the e
Darya [45]
Based on the equation, the coordinate point is (-4, 2). It is -4 because in the original equation, it's -x_{1}, but because it's positive, that must mean it was originally a negative. Why? Because a negative times an negative equals a positive.

Now, let's convert this to Slope-Intercept Form.

y - 2 = 2/3(x + 4)
y - 2 = 2/3x + 8/3
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The slope of the line is 2/3 and the original point was (-4, 2).

6 0
3 years ago
What’s the correct answer for this question?
Katena32 [7]

Answer:

C.

Step-by-step explanation:

It is the complement of the circle in the square

Okay,

Let the square be Universal set(U) and the circle be A

So

A complement = A' = U-A So

The shaded area is the complement of the circle

4 0
3 years ago
Divide these polynomials using long division.​
MariettaO [177]

The steps are more or less the same, except for one new addition:

1.Divide the tens column dividend by the divisor.

2.Multiply the divisor by the quotient in the tens place column.

3.Subtract the product from the divisor.

4.Bring down the dividend in the ones column and repeat.

5 0
3 years ago
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