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Gala2k [10]
3 years ago
7

The hypotnuse of a 45-45-90 triangle has a length of 10 units whats the length of one of its legs

Mathematics
1 answer:
mamaluj [8]3 years ago
7 0

Answer:

  5√2 units ≈ 7.07 units

Step-by-step explanation:

The ratio of leg to hypotenuse in an isosceles right triangle is ...

  leg/hypotenuse = 1/√2

Multiplying by the length of the hypotenuse, we have ...

  leg = hypotenuse/√2 = 10/√2

  leg = 5√2 . . . . rationalize the denominator

The length of one leg is 5√2 units, about 7.07107 units.

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Answer:

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Step-by-step explanation:

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SA = 2(5 · 6) + 2(6 · 3) + 2(5 · 3)

SA = 60 + 36 + 30

SA = 126 sq cm  

7 0
3 years ago
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ahrayia [7]

Answer:

The product of (-5·q·r) × (-2·p·q·r) × p·q is 10·q³·r²·p²

Step-by-step explanation:

The question relates to the rules of multiplication of variables and indices rules, and simplifification of an expression ;

The given expression is (-5·q·r) × (-2·p·q·r) × p·q

Therefore, we have;

(-5·q·r) × (-2·p·q·r) × p·q = (-5) × (-2) × q×q×q × r×r ×p×p = 10 × q³ × r² × p²

10 × q³ × r² × p² = 10·q³·r²·p²

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(-5·q·r) × (-2·p·q·r) × p·q = 10·q³·r²·p².

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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