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nikklg [1K]
3 years ago
13

Please answer right its very important!

Mathematics
2 answers:
Illusion [34]3 years ago
6 0

Answer:

- 37/100

Step-by-step explanation:

Since it's not a whole number it is over 100.

I hope this helped and if it did I would appreciate it if you marked me Brainliest. Thank you and have a nice day!

nordsb [41]3 years ago
3 0

Answer:

37/100

Step-by-step explanation: If you are trying to convert 0.37 then it is 37/100

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What are the solutions of the inequality? x/5 _>-2
nata0808 [166]
X is greater than -10
5 0
3 years ago
What is 2(6+7)= 3(5+2)
Komok [63]

Solution:

2(6+7)= 3(5+2)

Step ; 1 { Solving first Term i.e LHS }

LHS : 2 ( 6 + 7)

☞ 2 ( 13)

☞ 2 × 13

☞ 26

Now, RHS ; 3 ( 5 + 2)

☞ 3 ( 7)

☞ 21

From Equation 1 and 2, We can LHS and RHS are not Equal.

Therefore, 26≠ 21.

7 0
3 years ago
Suppose that a company needs 1, 200,000 items during a year and that preparation for each production run costs $500. Suppose als
MAVERICK [17]

Answer:

The number of items in each production run so that the total costs of production and storage are minimized is 8165 items/run

Step-by-step explanation:

We will use the following variables:

Q = Quantity being ordered

Q* = the optimal order Quantity: the result being sought

D = annual Demand for the item, over the year

P = unit Production cost

S = cost of setting up a production run, regardless of the number of units in the production run (fixed cost per production run)

H = annual cost to Hold one unit

It is important to note which variables are annualized, which are per-order and which are per-unit.

Using the variables, here are the components of the first equation

Total Cost, TC = PC + SC + HC

PC = P x D :  Production Cost = unit Production cost times the annual Demand

SC = (D x S)/Q : Setting up Cost = annual Demand times cost per production setup, divided by the order Quantity (number of units)

HC = (H x Q)/2: Holding Cost = annual unit Holding cost times order Quantity (number of units), divided by 2 (because throughout the year, on average the warehouse is half full).

So TC = PC + SC + HC =  (P x D) + ((D x S)/Q) + ((H x Q)/2) = PD + (DS/Q) + HQ/2

To obtain the optimal order quantity, Q* that minimizes TC, at the minimum TC, dTC/dQ = 0

dTC/dQ = (H/2) – (D x S)/(Q²) = 0

(H/2) – (D x S)/(Q²) = 0

Solving for Q, which is Q* at this point.

(Q*)² = 2DS/H

Q* = √(2DS/H)

D = annual demand for the item = 200000

S = cost of setting up a production run, regardless of the number of units in the production run (fixed cost per production run) = $500

H = annual cost to Hold one unit = $3

Q* = √(2×200000×500/3) = 8164.97 = 8165 items.

3 0
3 years ago
Help!!!! It’s due tom
bogdanovich [222]
The answer should be D.

The maximum amount she can add is 7 books and no more, so the first two are wrong. It’s also allowed to be exactly seven, which is why it would be a closed circle.

Hope this helps!
8 0
3 years ago
Find the angles of a rhombus if the ratio of the angles that the diagonals form with a side is 6:9.
fomenos

Answer:

The measures of the angles of the rhombus are 72° , 108° , 72° , 108°

Step-by-step explanation:

* Lets revise the properties of the rhombus

- It has 4 equal sides

- Each two opposite angles are equal

- Each two adjacent angles are supplementary (their sum = 180°)

- The diagonals are perpendicular to each other

- The diagonals bisect the vertices angles (divide each vertex into two

 equal parts)

* Now lets solve the problem

- Let the name of the rhombus is ABCD

- The two diagonals are AC and BD

- Let the diagonals AC and BD make the angles BAC and ABD with

 side AB

∵ The diagonals of the rhombus bisect the vertex angles

∴ m∠BAC is half m∠A

∴ m∠ABD is half m∠B

- There is a ratio between the measures of the angles BAC and ABD

∵ m∠BAC : m∠ABD = 6 : 9

∵ m∠A + m∠B = 180° ⇒ consecutive angles

∴ m∠BAC + m∠ABD = 1/2 × 180° = 90°

∵ m∠BAC : m∠ABD : their sum

         6     :       9      : 15⇒(6 + 9)

          ?    :        ?      : 90° ⇒(the sum of the angles)

∴ m∠BAC = 6/15 × 90° = 36°

∴ m∠ABD = 9/15 × 90° = 54°

∵ m∠BAC is half m∠A

∴ m∠A = 36° × 2 = 72°

∵ m∠ABD is half m∠B

∴ m∠B = 54° × 2 = 108°

* The measures of the angles of the rhombus are 72° , 108° , 72° , 108°

4 0
3 years ago
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