Answer and Explanation:
Solution:
Let x and y are independent, ariables.
The parameters of x and y are (n1, p) and (n2, p), respectively.
It means the sum of the independent binomial variable is itself a binomial random variable.
Consider probability of the event [ x = n1],
Denoted by: p(x=n1)
The function:
P(n1) = p(x = n1)
Over the possible value of x say, n1, n2, n3, …, is called frequency function.
The frequency function must satisfy.
∑I p (ni) = 1,
Where the sum is possible values of x.
Similarly,
Consider probability of the event [ y = n2],
Denoted by: p(y=n2)
The function:
P (n2) = p(y = n2)
Over the possible value of y say, n1, n2, n3, …, is called frequency function.
The frequency function completely describes the probabilistic nature of the random variable.
The average rate of change of f(x) on the interval [5, 5 + h] is 1
<h3>How to find the
average rate of change of f(x) on the interval [5, 5 + h]?</h3>
The equation of the function is given as:
f(x) = x + 11
The interval is given as: [5, 5 + h]
So, we start by calculating f(5) and f(5 + h)
This gives
f(5) = 5 + 11 = 16
f(5 + h) = 5 + h + 11 = h + 16
The average rate of change of f(x) on the interval [5, 5 + h] is then calculated as:
Rate = [f(5 + h) - f(5)]/[5 + h - 5]
Substitute the known values in the above equation
Rate = (h + 16 - 16)/(5 + h - 5)
Evaluate the sum and the difference
Rate = h/h
This gives
Rate = 1
Hence, the average rate of change of f(x) on the interval [5, 5 + h] is 1
Read more about the average rate of change at
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