Points (1, 7) and (-3, 2)
Slope for a line between (x₁, y₁) and (x₂, y₂) , m = (y₂ -y₁) / (x₂- x₁)
The slope for the line joining the two points = (2 - 7) / (-3 - 1) = -5/-4
Slope = 5/4
Hence the perpendicular bisector would have a slope of -1/(5/4) = -4/5
By condition of perpendicularity
For points (1, 7) and (-3, 2),
Formula for midpoints for (x₁, y₁) and (x₂, y₂) is ((x₁ +x₂)/2 , (y₁+ y₂)/2)
Midpoint for (1, 7) and (-3, 2) = ((1+ -3)/2 , (7+2)/2) = (-2/2, 9/2)
= (-1, 9/2)
Since the slope of perpendicular bisector is -4/5 and passes through the midpoint (-1, 9/2)
Equation y - y₁ = m (x - x₁)
y - 9/2 = (-4/5) (x - -1)
y - 9/2 = (-4/5)(x + 1)
5(y - 9/2) = -4(x + 1)
5y - 45/2 = -4x - 4
5y = -4x - 4 + 45/2
5y + 4x = 45/2 - 4
5y + 4x = 22 1/2 - 4 = 18 1/2
5y + 4x = 37/2
10y + 8x = 37
The equation of the line to perpendicular bisector is 10y + 8x = 37
Answer:
y = 1/2x - 5
Step-by-step explanation:
I'm going to use slope-intercept form. Your y-intercept is already shown when x is zero, which is (0,-5). Your slope is defined as rise over run, so 1/2 in this case. This gives you an equation of f(x) = 1/2x-5
I supose your function is:

Step 1. Replace the coordinates of the first point in your equation:
x=-2, y=3

Solve the equation for "a":

Step 2. Replace the coordinates of the second point in your equation:
x=6, y=35
Replace the value of "a" from Step 1.

Calculate "b":
![b= \sqrt[8]{\frac{35}{3}} = 1.359466](https://tex.z-dn.net/?f=b%3D%20%5Csqrt%5B8%5D%7B%5Cfrac%7B35%7D%7B3%7D%7D%20%3D%201.359466)
Step 3. Replace "b" in first equation and calculate "a":

The equation is: