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frosja888 [35]
3 years ago
5

A first number plus twice a second number is 4. Twice the first number plus the second totals 20. Find the numbers

Mathematics
1 answer:
pychu [463]3 years ago
4 0

Answer:

The first number is 6

The second number is -1

6+(-2)=4

6*2=12 12+(-1)=11

Step-by-step explanation:


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Expand.<br> Your answer should be a polynomial in standard form.<br> (x-3)(x-4)=
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Answer:

Step-by-step explanation:

So, it's x*x+x*-3+-4*x+3*-3

That simplifies to x^2 - 7x + 12

5 0
3 years ago
3 times the difference between ten times a number and three is eighty one? Find the number
bixtya [17]
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7 0
3 years ago
What is the value of x for the equation x+2/4 + 1/3 = 2x-1/6
Gnoma [55]

Answer:

1

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

x+24+13=2x−16

x+ 1 2 + 1 3 =2x+ −1 6

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x+ 5 6 =2x+ −1 6

x+ 5 6 =2x+ −1 6

Step 2: Subtract 2x from both sides.

x+ 5 6 −2x=2x+ −1 6 −2x

−x+ 5 6 = −1 6

Step 3: Subtract 5/6 from both sides.

−x+ 5 6 − 5 6 = −1 6 − 5 6

−x=−1

Step 4: Divide both sides by -1.

−x −1 = −1 −1

x=1

7 0
3 years ago
Read 2 more answers
For better clarification I guess
marissa [1.9K]

Answer:

1.) =\frac{\sqrt{3}}{3}

2.) 42\sqrt{30}

Step-by-step explanation:

1.) \mathrm{Multiply\:by\:the\:conjugate}\:\frac{\sqrt{3}}{\sqrt{3}}

2.) \mathrm{Apply\:radical\:rule}:\quad \sqrt{a}\sqrt{b}=\sqrt{a\cdot b}

\sqrt{6}\sqrt{5}=\sqrt{6\cdot \:5}

6 0
3 years ago
Find two consecutive even integers whose sum is 22
andrew11 [14]

10 & 12

x = 1st consecutive even number

x + 2 = 2nd consecutive even number  

x + x + 2 = 22

2x + 2 = 22

2x = 20

x = 10

x + 2 = 12

10 and 12 are the two consecutive even numbers



7 0
3 years ago
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