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IceJOKER [234]
3 years ago
7

How do I solve this using the substitution method for finding anti derivatives?

Mathematics
1 answer:
rewona [7]3 years ago
6 0
A bit blurry, but if I'm making it out correctly, that's

\displaystyle\int t\sqrt{(t^2-9)^3}\,\mathrm dt=\int t(t^2-9)^{3/2}\,\mathrm dt

Set u=t^2-9. Then \mathrm du=2t\,\mathrm dt, or t\,\mathrm dt=\dfrac{\mathrm du}2. The integral is then equivalent to

\displaystyle u^{3/2}\dfrac{\mathrm du}2=\frac12\int u^{3/2}\,\mathrm du
=\dfrac12\dfrac{u^{5/2}}{\frac52}+C
=\dfrac12\times\dfrac25u^{5/2}+C
=\dfrac15u^{5/2}+C
=\dfrac15(t^2-9)^{5/2}+C
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8 0
3 years ago
6. Find the product:<br> (x² + 8x - 3)(x + 1)
olga_2 [115]

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Step-by-step explanation:

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8 0
3 years ago
Can someone help me please.
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28. the second and third one

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