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3 years ago

11

A local club team is holding tryouts for six spots on the soccer team. Since there is not much time before a very important tour

nament they need to select the best players. Which method would be the best to ensure they select the "most talented" soccer players?

1 answer:

fenix001 [56]3 years ago

7 0

Having them play against the best players already on the team and seeing who holds up best.

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Express 3/4 in sixty- fourths

Marrrta [24]

If you want 3/4 in 64's, multiply the numerator (3) by 16, as 4 x 16 = 64.

<span>3 x 16 </span>
<span>--------- </span>
<span>4 x 16 </span>

<span>= 48/64</span>

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3 years ago

How do I do this problem??

Montano1993 [528]

The answer to this problem is 1 :)

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3 years ago

A particular state has elected both a governor and a senator. Let A be the event that a randomly selected voter has a favorable

Elodia [21]

Answer:

Step-by-step explanation:

Given that A be the event that a randomly selected voter has a favorable view of a certain party’s senatorial candidate, and let B be the corresponding event for that party’s gubernatorial candidate.

Suppose that

P(A′) = .44, P(B′) = .57, and P(A ⋃ B) = .68

From the above we can find out

P(A) = $1-0.44 = 0.56$

P(B) = $1-0.57 = 0.43$

P(AUB) = 0.68 =

$0.56+0.43-P(A\bigcap B)\\P(A\bigcap B)=0.30$

a) the probability that a randomly selected voter has a favorable view of both candidates=P(AB) = 0.30

b) the probability that a randomly selected voter has a favorable view of exactly one of these candidates

= P(A)-P(AB)+P(B)-P(AB)

$=0.99-0.30-0.30\\=0.39$

c) the probability that a randomly selected voter has an unfavorable view of at least one of these candidates

=P(A'UB') = P(AB)'

= $1-0.30\\=0.70$

3 0

3 years ago

I NEED THIS IN 12 MINUTES<br> what is on flvs module 3 dba for preabgabra

GarryVolchara [31]

Answer:

Greatest Common Factor: integer or variable multiplied by other integers or variables that creat a resultin product. factor x factor = product

difference of squares binomial: an expression where two perfect square terms are being subtracteda² - b² = (a+b)(a-b)quadratic: from "quad" meaning square, because the variable gets squared (like x2).

discriminant: tells you about the roots of a quadratic

general form: y = a(x - h)^2 + kstandard form: ax^2 + bx + c = 0root: a solution of an equation

zero: a value that gives you 0 for a function

x-intercept: where the graph crosses the x-axis

y-intercept: where the graph crosses the y-axis

extraneous: a solution that does not work

parabola: the graph of a quadratic

vertex: the turning point of the parabola

axis: line of reflection

translation: movement up/down and left/right of any parabola from standard position (f(x) = x2)

The basics of what you should know

Step-by-step explanation:

Can get brainiest pls

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3 years ago

At a farm, the average number of chickens, ducks, rabbits and sheep is 315 per type of animal. The average number of chickens, d

Greeley [361]

The average number of chickens, ducks, rabbits and sheep = 315 per type of animal.

The average number of chickens, ducks and rabbits = 320 per type of animal.

The number of sheep is 60 more than the number of rabbits.

Let us assume number of rabbits = x.

Number of sheep is 60 more than number of rabbits, that is = x+60.

There are half as many ducks as there are rabbits.

Therefore, number of ducks = x/2.

Let us assume number of chickens = y.

Adding number of chickens, number of rabbits, number of sheep and number of ducks and dividing by 4 (because those are four types of animal).

$\frac{y+x+x+60+x/2}{4} = 315$

Multiplying both sides by 4, we get

y+x+x+60+x/2 = 1260

Subtracting 60 from both sides

y+x+x+60-60+x/2 = 1260-60

y+x+x+x/2 = 1200.

Combining like terms .

y + 5x/2 = 1200

Multiplying both sides by 2, we get

<em>2y +5x = 2400 ------------equation (1)</em>

Adding number of chickens, number of rabbits and number of ducks and dividing by 3 (because those are three types of animal).

$\frac{y+x+60+x/2}{3} = 320$

Multiplying both sides by 3, we get

y+x+60+x/2 = 960

Subtracting 60 from both sides

y+ x+x/2 = 900

Combining like terms .

y+ 3x/2 = 900

Multiplying both sides by 2, we get

<em>2y+3x = 1800 --------------------equation (2)</em>

Multiplying first equation by 3 and second equation by -5, we get

(2y +5x = 2400 ) * 3 => 6y +15x = 7200

(2y+3x = 1800) *-5 =>

Adding

6y +15x = 7200

-10x + -15x = -9000.

_________________

-4y = -1800.

Dividing both sides by -4, we get

y=450.

<h3>Therefore, number of chickens are 450 there at the farm.</h3>

7 0

3 years ago