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3 years ago

11

A local club team is holding tryouts for six spots on the soccer team. Since there is not much time before a very important tour

nament they need to select the best players. Which method would be the best to ensure they select the "most talented" soccer players?

1 answer:

fenix001 [56]3 years ago

7 0

Having them play against the best players already on the team and seeing who holds up best.

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Mark has $100,000 to invest. His financial consultant advises him to diversify his investment in three types of bonds: short-ter

galina1969 [7]

Answer:

Short-Term investment: 5000$

Intermediate-Term investment: 65000$

Long-Term investment: 30000$

Step-by-step explanation:

To construct our first equation lets define sort-term bond investment as x, long-term investment as y.

So the equation is:

$x*0,04+(100000-x-y)*0,05+y*0,06=5250$

From the equation it is found that:

$y=25000+x$

Instead of y, if we put 25000+x the equation will be as following:

$x*0,04+75000*0,05+(25000+x)*0,06=5250$

From the equation it is found that:

$x=5000$

Short-Term investment is 5000$

$x+25000=y$

Long-Term investment is 30000$

Rest of the money is Intermediate-Term investment 65000$

5 0

3 years ago

All models are reductions of the original object.<br> True<br> False

viktelen [127]

Answer:

true

Step-by-step explanation:

models are a smaller example of an original object

3 0

2 years ago

Read 2 more answers

A family needs to cross a river in a small raft.

serg [7]

Answer:

so basically you can take more than one trip you can take the mother and the bag at the same time

Step-by-step explanation:

and then you can get the daughter in the son at the same time and then for the final trip you take the father by himself

8 0

2 years ago

a bag holds 1200 marbles colored either blue, red, green, or pink. there are 2 more blue than green, 6 more green than red and 6

krek1111 [17]

B = 2 + g . . . (1)
g = 6 + r . . . (2)
r = 6 + p . . . (3)

Putting (3) into (2) gives:
g = 6 + 6 + p = 12 + p . . . (4)
Putting (4) into (1) gives:
b = 2 + 12 + p = 14 + p . . . (5)

b + g + r + p = 1200
2 + g + 6 + r + 6 + p + p = 1200
2 + 12 + p + 6 + 6 + p + 6 + p + p = 1200
32 + 4p = 1200
4p = 1200 - 32 = 1168
p = 292

From (5), b = 14 + p = 14 + 292 = 306

Therefore, there are 306 blue mables.

8 0

3 years ago

A certain number of sixes and nines is added to give a sum of 126; if the number of sixes and nines is interchanged, the new sum

galina1969 [7]

Answer:

Original number of sixes = 6

Original number of nines = 10

Step-by-step explanation:

We are told in the question that:

A certain number of sixes and nines is added to give a sum of 126

Let us represent originally

the number of sixes = a

the number of nines = b

Hence:

6 × a + 9 × b = 126

6a + 9b = 126.....Equation 1

If the number of sixes and nines is interchanged, the new sum is 114.

For this second part, because it is interchanged,

Let us represent

the number of sixes = b

the number of nines = a

6 × b + 9 × a = 114

6b + 9a = 114.......Equation 2

9a + 6b = 114 .......Equation 2

6a + 9b = 126.....Equation 1

9a + 6b = 114 .......Equation 2

We solve using Elimination method

Multiply Equation 1 by the coefficient of a in Equation 2

Multiply Equation 2 by the coefficient of a in Equation 1

6a + 9b = 126.....Equation 1 × 9

9a + 6b = 114 .......Equation 2 × 6

54a + 81b = 1134 ........ Equation 3

54a + 36b = 684.........Equation 4

Subtract Equation 4 from Equation 3

= 45b = 450

divide both sides by b

45b/45 = 450/45

b = 10

Therefore, since the original the number of nines = b,

Original number of nines = 10

Also, to find the original number of sixes = a

We substitute 10 for b in Equation 1

6a + 9b = 126.....Equation 1

6a + 9 × 10 = 126

6a + 90 = 126

6a = 126 - 90

6a = 36

a = 36/6

a = 6

Therefore, the original number of sixes is 6

7 0

3 years ago