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3 years ago

14

John has five times as many nickels as quarters and three times as many dimes as quarters. The total value of the coins is $8. H

ow many of each coin does he have

1 answer:

Elena L [17]3 years ago

7 0

Answer:

4 quarters

20 Nickels

60 dimes

Step-by-step explanation:

4Q x 5 = 20N

20N x 3 = 60D

add them in to dollars you get one dollar each from the nickels and quarters and 6 dollars from the dimes.

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Last year Mr. Ingles total income was 52000+ total expenses were 53800 use expression I-E/12 where I represents total income in

Olegator [25]

Answer:

-$150

Step-by-step explanation:

Given:

(I - E) / 12

Where,

I = total income

E = total expenses

I = $52,000

E = $53,800

(I - E) / 12

= (52,000 - 53,800) / 12

= -1,800 / 12

= -150

-$150 shows that Mr. Engle's total expenses exceeds his total income per month with an average of $150

8 0

3 years ago

Find f(-3), f(-1), and f(1)

suter [353]

Answer:

I will just show you how to substitute.

Step-by-step explanation:

all you have to do is just plug f(x) into the number you want. So if you see any x's, all you gotta do is plug that number after f for x.

So an example of an equation for one of your number is:

$f\left(x\right)=x^2+x$

you then want to plug the number after f for the x's. (I'm doing f(-3).

$f\left(-3\right)=\left(-3\right)^2-3$

You then should get the equation above.

after that you solve.

$f\left(-3\right)=9-3$

$f\left(-3\right)=6$

just follow these steps and you should be fine :))

3 0

4 years ago

Show work! giving brainly! my teacher told me this was wrong, what's the correct answer?

Luba_88 [7]

Your not wrong I don’t know why your teacher said that

7 0

3 years ago

Read 2 more answers

James is a quality control specialist. He is required to check 180 rubber balls out of a shipment of 18,000 for defects. He find

dedylja [7]

That 3 out of 180 are defected

6 0

3 years ago

Select the two values of x that are roots of this equation.<br> x2 - – 5x + 5 = 0

umka21 [38]

Answer:

Using the Quadratic Formula

x=-b ± √b²-4ac/[2a]

x= -(-5) ± √5² - 4(1)(5)/(2)

x= 5 ± √25-20 /(2)

x= 5 ± √5 /(2)

x= 5 + √5/(2) and 5 - √5/(2)

Answer

B and C

3 0

3 years ago