A number minus twenty four
Answer:
(2b-3)²
Step-by-step explanation:
The square of a binomial is ...
(p - q)² = p² - 2pq + q²
The fact that the first and last terms are perfect squares suggests that you might want to look to see if the middle term matches this form. It does.
For p² = 4b², p=2b.
For q² = 9, q = 3.
Then 2pq = 2(2b)(3) = 12b.
So, the factoring is ...
4b² -12b +9 = (2b -3)²
0.5 as a decimal
hope this partially helped:)
sorry couldn't answer completely
let me know if it helped a bit:)
An 8th-degree polynomial needs 9 terms that involve
x⁸, x⁷, ..., x¹, and x⁰.
x=10 implies that (x-10) is a factor of the polynomial according to the Remainder theorem.
Let the polynomial be of the form
f(x) = a₁x⁸ + a₂x⁷ + a₃x⁶ +a₄x⁵ + a₅x⁴ + a₆x³ + a₇x² + a₈x + a₉
The first few lines of the synthetic division are
10 | a₁ a₂ a₃ a₄ a₅ a₆ a₇ a₈ a₉ ( the first row has 9 coefficients)
-----------------------------------------
a₁
Answer:
The first row has 9 coefficients.
Answer:
a. a = 1, b = -5, c = -14
b. a = 1, b = -6, c = 9
c. a = -1, b = -1, c = -3
d. a = 1, b = 0, c = -1
e. a = 1, b = 0, c = -3
Step-by-step explanation:
a. x-ints at 7 and -2
this means that our quadratic equation must factor to:

FOIL:

Simplify:

a = 1, b = -5, c = -14
b. one x-int at 3
this means that the equation will factor to:

FOIL:

Simplify:

a = 1, b = -6, c = 9
c. no x-int and negative y must be less than 0
This means that our vertex must be below the x-axis and our parabola must point down
There are many equations for this, but one could be:

a = -1, b = -1, c = -3
d. one positive x-int, one negative x-int
We can use any x-intercepts, so let's just use -1 and 1
The equation will factor to:

This is a perfect square
FOIL:

a = 1, b = 0, c = -1
e. x-int at 
our equation will factor to:

This is also a perfect square
FOIL and you will get:

a = 1, b = 0, c = -3