Answer:

where
= 2
Step-by-step explanation:
512/-8 = -64
difference of n = 3
![\sqrt[3]{64} = 4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B64%7D%20%3D%204)

where
= 2
To calculate the IQR, we need the radian, which is the middle number of each column, namely (86,82) for each exam.
Above the middle number, we have 5 values. The middle value (of the upper part) is Q3, which is on the third line, or (92,85).
Below the middle number, we also have 5 values. The middle (of the lower half) is Q1, which is on the 9th line (80,78)
The IQR is the difference between Q3 and Q1, namely
(92-80, 85-78) = (12, 7)
Since 12>7, we conclude that the IQR of the mid-term is higher than the final.
Answer:
12a^2+18ab-6ac+25a-3b+c
Step-by-step explanation:
Ani dont know
Step-by-step explanation: