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2 years ago

What is the missing number in the number sentence?

Mathematics

2 answers:

MatroZZZ [7]2 years ago

8 0

Answer:

the missing number is 47............

stepladder [879]2 years ago

7 0

Answer:

Step-by-step explanation:

46+10=56. That means that ?+9 needs to equal 56.

56-9=47 which is the missing number.

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5 is the same as ___ and ___.

nirvana33 [79]

1/2 and 1/3 1/4. Is the answer I automatically thought of

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3 years ago

A 16 ounce bag of cereal cost $2.88 what is the cost per ounce

BabaBlast [244]

Answer: 0.18 (18 cents) per ounce

Step-by-step explanation:

2.88/16 = 0.18

5 0

3 years ago

Two trains are traveling at a constant rate. Which train has the greater speed?

natali 33 [55]

A point on the graph (for train b) that is exact is (2,250). From the origin, the rise is 250 and the run is 2. Rise/run would give us 250/2, which is 125. This means that train B travels 125mi every hour. For train A, we subtract the distance from hour 2 from hour 3 to get the miles per hour (because 3-2=1, subtracting the distance of hour 3 from 2 will give us the distance in 1 hour). 180-120= 60, meaning train A travels at 60mph. 60<125, meaning A

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3 years ago

May someone assist me?

raketka [301]

Answer:

<h2><u><em>15 is the answer.</em></u></h2>

Step-by-step explanation:

The side lengths are equal - supposedly

30 25

? ?

25 + ? = 45

-25 - 25

? = 20

45 - 30 = 15

The question mark should be equal to 15.

Hope this helps,

Kavitha

3 0

3 years ago

The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis

Firdavs [7]

Answer:

$sin\theta_1 = - \frac{2\sqrt{70}}{19}$

Step-by-step explanation:

We are given that $\theta_1$ is in <em>fourth</em> quadrant.

$cos\theta_1$ is always positive in 4th quadrant and

$sin\theta_1$ is always negative in 4th quadrant.

Also, we know the following identity about $sin\theta$ and $cos\theta$ :

$sin^2\theta + cos^2\theta = 1$

Using \theta_1 in place of \theta:

$sin^2\theta_1 + cos^2\theta_1 = 1$

We are given that $cos\theta_1 = \frac{9}{19}$

$\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{280}{361}\\\Rightarrow sin\theta_1 = \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}$

$\theta_1$ is in <em>4th quadrant </em>so $sin\theta_1$ is negative.

So, value of $sin\theta_1 = - \frac{2\sqrt{70}}{19}$

6 0

3 years ago