Answer:
85%
Step-by-step explanation:
The discount is 15% which we can write as 0.15 and we multiply that by 30 to get the discount, which is $4.50. We subtract that from the original price; 30 to get $25.50 as the sale price. We want to find out what percent of 30 25.50 is, so we divide 25.50 and 30 to get 0.85. Multiply that by 100 to get 85%.
350 ÷ 6 = 58.33
58.33 pounds of chocolate per hour
58.33 × 10 = 583.3
583.33 pounds of chocolate in 10 hours
Answer:
x>24
Step-by-step explanation:
Solve like a normal equation :)
-2x<-48
Now we divide.
-x<-24
Note: Whenever dividing by a negative, you have to flip the sign of the inequality!
x>24
The expected length of code for one encoded symbol is
where 
is the probability of picking the letter 
, and 
is the length of code needed to encode . is given to us, and we have
so that we expect a contribution of
bits to the code per encoded letter. For a string of length 
, we would then expect ![E[L]=1.375n](https://tex.z-dn.net/?f=E%5BL%5D%3D1.375n)
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have
so that the variance for the length such a string is
"squared" bits per encoded letter. For a string of length , we would get ![\mathrm{Var}[L]=1.859n](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3D1.859n)
.
Answer:
4/5
Step-by-step explanation:
formula for slope is (y2-y1)/(x2-x1)
