You can solve for the velocity and position functions by integrating using the fundamental theorem of calculus:
<em>a(t)</em> = 40 ft/s²
<em>v(t)</em> = <em>v </em>(0) + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
<em>v(t)</em> = -20 ft/s + ∫₀ᵗ (40 ft/s²) d<em>u</em>
<em>v(t)</em> = -20 ft/s + (40 ft/s²) <em>t</em>
<em />
<em>s(t)</em> = <em>s </em>(0) + ∫₀ᵗ <em>v(u)</em> d<em>u</em>
<em>s(t)</em> = 10 ft + ∫₀ᵗ (-20 ft/s + (40 ft/s²) <em>u</em> ) d<em>u</em>
<em>s(t)</em> = 10 ft + (-20 ft/s) <em>t</em> + 1/2 (40 ft/s²) <em>t</em> ²
<em>s(t)</em> = 10 ft - (20 ft/s) <em>t</em> + (20 ft/s²) <em>t</em> ²
Answer:
The reflection image of P(0, 0) after two reflections is (8,-6)
Step-by-step explanation:
step 1
Find the coordinates of point P after reflection across x=4
we know that
The distance from point P to the line x=4 is equal to 4 units
so
(0,0) -----> (4+4,0) ----> (8,0)
The reflection image of P is (8,0)
step 2
Find the coordinates of point (8,0) after reflection across y=-3
The distance from point (8,0) to the line y=-3 is equal to 3 units
so
(8,0) -----> (8,-3-3) ----> (8,-6)
A) 144 in
is your answer. good luck
Answer:
5/19
Step-by-step explanation:
There's no explanation, it's just common sense ♀️
Assignment: 
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Answer: 
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Explanation: 
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[ Step One ] Remove Parenthesis (a) = a
[ Step Two ] Simplify Equations
[ Step Three ] Rewrite Equation
[ Step Four ] Add Similar Elements
[ Step Five ] Rewrite Equation
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