Ask question

Ask question

All categories

brilliants [131]

3 years ago

9

Members of the Wide Water Club pay $105 per summer season, plus $9.50 each they rent a boat. Nonmembers must pay $14.75 each tim

e they rent a boat. How many times would a member have to renta boat in order to pay the same amount.

1 answer:

avanturin [10]3 years ago

7 0

In order to pay the same amount each member would have to rent a boat out 20 times.

You might be interested in

If you scale a figure by less than or less than 100% does the new copy increase or decrease in size? PLS HURRY IT'S LATE PLS I D

prisoha [69]

Answer:

Less

Step-by-step explanation:

100% is full size

6 0

2 years ago

Find the prime factorization on 168

Paha777 [63]

Answer:

The prime factors of 168 are 2, 3, and 7.

Step-by-step explanation:

4 0

3 years ago

Ashley deposits $1000 into an account that earns 4% interest compounded 2 times per year. How much money will Ashley have in her

vlabodo [156]

That would be C. $1218.99 :)

5 0

3 years ago

Read 2 more answers

Prove the trigonometric identity

Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

$1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1$

Lets solve the bottom most part first:

$1-\frac{1}{1-sec^2x} \\\\$

Take LCM

$1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}$

now break the LCM

$\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1$

because 1/tan = cot x

and furthermore,

$cot^2x+1\\cosec^2x$

now we solve the above part and replace the bottom most part that we solved with $cosec^2x$

$\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x$

Hence proved! :D

4 0

3 years ago

What is the fifth term in the geometric sequence described by this explicit formula y=40×(-2)^(n-1)

cupoosta [38]

Answer:

The fifth term is 620

Step-by-step explanation:

y=40×(-2)^(n-1)

The 5th terms means n=5

y = 40 * (-2) ^ (5-1)

= 40 * (-2) ^4

= 40 * (16)

= 640

5 0

3 years ago