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kolbaska11 [484]
3 years ago
13

Simplify the following expression. 2x + 3x3 - 5x2 + x2 +7x + 1+ 7x -3x3 - 4

Mathematics
2 answers:
denis-greek [22]3 years ago
8 0

-4x^2+16x-3 is your answer

jek_recluse [69]3 years ago
4 0

Answer:

-4x^2 +16x -3

Step-by-step explanation:

2x + 3x^3 - 5x^2 + x^2 +7x + 1+ 7x -3x^3 - 4

Line up the numbers in decreasing power

3x^3 -3x^3 - 5x^2  + x^2 +7x +2x+ 7x - 4+1

Combine like terms

-4x^2 +16x -3

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The taxi ride costs $3.00 plus
sleet_krkn [62]

Answer:

$7

because theres 4 quarters in a mile so one mile would equal to $2  bc

0.50 x 4 = $2

and you have to go 2 miles so

$2 + $2 = $4

then you add the the cost of the taxi so

$4+ $3

= $7

3 0
2 years ago
2 in., 3 in., 6 in.<br> can a triangle have sides with the given lengths
Rainbow [258]

Answer:

No because the 6+4 does not equal 36.

Step-by-step explanation:

first make the hypotenuse 6 the other two are sides A and B

Use the pythagorean theorem: 3^2+2^2+6^2

6+4=36

3 0
3 years ago
How do i solve these and graph them ?!
Ainat [17]
Use Desmos. It is good.

Here is the graph.
https://www.desmos.com/calculator/wq4kzps9fq

To change the color, you have to click on the line next to the formula for a long time. A window will pop up so you can change the color.
4 0
3 years ago
Find MO and PR <br> ............................................................
ddd [48]

MO = 12 and PR = 3

Solution:

Given \triangle M N O \sim \Delta P Q R.

Perimeter of ΔMNO = 48

Perimeter of ΔPQR = 12

MO = 12x and PR = x + 2

<em>If two triangles are similar, then the ratio of corresponding sides is equal to the ratio of perimeter of the triangles.</em>

$\Rightarrow \frac{\text{Perimeter of }\triangle MNO}{\text{Perimeter of }\triangle PQR} =\frac{MO}{PR}

$\Rightarrow \frac{48}{12} =\frac{12x}{x+2}

Do cross multiplication.

$\Rightarrow 48({x+2})= 12(12x)

$\Rightarrow 48x+96= 144x

Subtract 48x from both sides.

$\Rightarrow 48x+96-48x= 144x-48x

$\Rightarrow 96= 96x

Divide by 96 on both sides, we get

⇒ 1 = x

⇒ x = 1

Substitute x = 1 in MO an PR.

MO = 12(1) = 12

PR = 1 + 2 = 3

Therefore MO = 12 and PR = 3.

7 0
3 years ago
Does anyone know how to simplify this expression? I know it has to do with properties of summation and special summation rules b
dusya [7]
<h3>Answer:     -n/(n+1)</h3>

============================================================

Explanation:

Let's expand this out up to say n = 6 terms

I'll write the summation in such a way that each (1/(k+1) - 1/k) grouping will get its own row. Each row has the same value of k.

If we plug in k = 1 through k = 6, but not evaluate just yet, we will have this:

1/(1+1) - 1/1

1/(2+1) - 1/2

1/(3+1) - 1/3

1/(4+1) - 1/4

1/(5+1) - 1/5

1/(6+1) - 1/6

All I've done so far is replace k with 1 through 6. Again, each row represents a different k value. Each row has the general format 1/(k+1)-1/k.

Let's simplify everything in the first column.

So the (1+1) turns into 2, the (2+1) turns into 3, and so on.

Doing that leads to...

1/2 - 1/1

1/3 - 1/2

1/4 - 1/3

1/5 - 1/4

1/6 - 1/5

1/7 - 1/6

Then note how we have the cancellations shown in the diagram below. The color coding shows how the terms pair up to cancel out. By "cancel out", I mean specifically that the fractions add up to 0. Eg: 1/2 + (-1/2) = 0.

Nearly everything cancels out. The only things left after the dust settles is the -1/1 in the first row and the 1/7 in the bottom row. This evaluates to 1/7-1/1 = 1/7 - 7/7 = (1-7)/1 = -6/7

If you were to try this with n = 7, then you should find that again nearly everything cancels but the fractions -1/1 and 1/8. Then 1/8 - 1/1 = -7/8.

For n = 8, you should end up with 1/9 - 1/1 = -8/9.

You can probably see the pattern.

A conjecture is that the answer is -n/(n+1). The general proof of this isn't too tricky. Simply follow the same ideas as mentioned above. Expand out a few terms and see how things cancel out. You'll find that everything cancels except for the -1/1 in the first row and the 1/(n+1) just one term before the very end. Then we can say:

1/(n+1) - 1/1

1/(n+1) - (n+1)/(n+1)

(1-(n+1))/(n+1)

(1-n-1)/(n+1)

-n/(n+1)

If we tried n = 6, then we find,

-n/(n+1) = -6/(6+1) = -6/7

which was the result we found earlier when we added the first n = 6 terms of this series. Trying out n = 7 should lead to -n/(n+1) = -7/8, and so on.

3 0
3 years ago
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