L=w+2 and 2w+2l=44
substitute equation for length in perimeter equation
2w+2(w+2)=44
2w+2w+4=44
4w+4=44
4w=40
w=10
substitute width into length equation to get length
l=10+2
l=12
a=lw
a=12*10
a=120 cm^2
-- point (1, -2)
-- point (10, 25)
Answer:
Step-by-step explanation:
1 Answer. Reflection does not preserve orientation. Dilation (scaling), rotation and translation (shift) do preserve it.
Answer:
Area of Poster = 23 sq inches
Step-by-step explanation:
Let say Width of Rectangular Poster = W inches
then Length of Rectangular Post = 2W inches
Perimeter = 2 ( W + 2W) = 6W inches
Perimeter given = 12 inches
Equating both
6W = 24
=> W = 4
Width of Poster = W = 4 Inches
Length of Poster = 2W = 2 * 4 = 8 inches
Area of Poster = 4 * 8 = 32 sq inches
Answer:I dont know not gonna lie
Step-by-step explanation:
