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3 years ago

What is 2/3×-6×5 for math

Mathematics

2 answers:

guajiro [1.7K]3 years ago

7 0

Answer: -20...I Think Sir...

Step-by-step explanation:

ratelena [41]3 years ago

7 0

Answer:

It's -20

Step-by-step explanation:

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Charlotte has appointed a chairperson to lead a city beautification project. The first act is to install statues and fountains i

miskamm [114]

Answer:

Net Income of $6,800,000

Increase in Accounts Payable of $200,000

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Assuming no other cash flow adjustments than those listed above, create a statement of cash flows with amounts in thousands....

Step-by-step explanation:

<h2>plz bhai mera answer ko brainliest kar do...</h2>

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3 years ago

the diagram gives the dimensions of a swimming pool.if a cover is needee for the pool, what will be the approximate area of the

mars1129 [50]

The answer is 360 because if u do this 20×36 and the 1/2 it u get this 360 20×36 is 720 and then 2÷720 u get 360

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3 years ago

The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop

Anettt [7]

Answer:

a. $\frac{1}{15}$

b. $\frac{2}{5}$

c. $\frac{14}{15}$

d. $\frac{8}{15}$

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

a. Favorable cases for Both the laptops to be selected = $_2C_2$ = 1

Total number of cases = 15

Required probability is $\frac{1}{15}$ .

b. Favorable cases for both the desktop machines selected = $_4C_2=6$

Total number of cases = 15

Required probability is $\frac{6}{15} = \frac{2}{5}$ .

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

2. Both desktop:

Favorable cases = $_4C_2=6$

Total number of favorable cases = 8 + 6 = 14

Required probability is $\frac{14}{15}$ .

d. 1 desktop and 1 laptop:

Favorable cases = $_2C_1\times _4C_1 = 8$

Total number of cases = 15

Required probability is $\frac{8}{15}$ .

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3 years ago

Multiply. <br> (5x - 2)(8x + 3) <br> Enter your answer, in standard form, in the box.

ziro4ka [17]

Standard form:

40x^2−x−6

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2 years ago

Mai runs around a track at a constant speed of 750 meters in 30 minutes . How many minutes per meter is that? And how many meter

Rudik [331]

Answer:

25 meters per minute

150 in 6 minutes

Step-by-step explanation:

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3 years ago