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Gnesinka [82]
3 years ago
13

What is 2/3×-6×5 for math

Mathematics
2 answers:
guajiro [1.7K]3 years ago
7 0

Answer: -20...I Think Sir...


Step-by-step explanation:


ratelena [41]3 years ago
7 0

Answer:

It's -20

Step-by-step explanation:


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can someone please help with my geometry homework?? i haven't been in the class for a year and i'm starting off the second semes
sattari [20]
Ok so for number 5, AB is proportional to BC just like PQ is proportional to QR. AB = 9, BC = 15, PQ = 3, and QR = x. 9/15 = 3/x. Cross Multiply: This gives you - 9x = 45. Divide both sides by 9, and you get x = 5. QR = 5
3 0
3 years ago
How much is 5.802 less than 74.14<br>​
Wewaii [24]

Answer:

68.338

Step-by-step explanation:

to know how much is less than we have to substract

74.14-5.802=68.338

4 0
3 years ago
How do you find the Median Absolute and Deviation
Ivenika [448]

Answer:

Calculate Mean Absolute Deviation (M.A.D)

Step-by-step explanation:

To find the mean absolute deviation of the data, start by finding the mean of the data set.Find the sum of the data values, and divide the sum by the number of data values.Find the absolute value of the difference between each data value and the mean: |data value – mean|.

4 0
3 years ago
How do you find the lease common fatcor
8_murik_8 [283]

Answer:

One way to find the least common multiple of two numbers is to first list the prime factors of each number. Then multiply each factor the greatest number of times it occurs in either number. If the same factor occurs more than once in both numbers, you multiply the factor the greatest number of times it occurs.


Step-by-step explanation:


4 0
4 years ago
For a school fundraiser students are selling snack bags and candy bars to raise money on Wednesday the students or 23 snack bags
meriva

Answer:

$1.75

Step-by-step explanation:

The selling for each candy bar may be determined by  a set of linear equations. This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.

It may be solved by substitution in that one of the variable is made the subject of the equation and the result is substituted into the second equation .

Let the cost of a snack bag be s and that of a candy bar be c, then if on Wednesday the students or 23 snack bags and 36 candy bars that raised $114.75 on Thursday the seventh so 37 snack bags and 36 candy bars that raised $146.25

23s + 36c = 114.75

37s + 36c = 146.25

14s = 31.5

s = $2.25

23(2.25) + 36c = 114.75

36c = 114.75 - 51.75

36c = 63

c = 63/36

= $1.75

3 0
3 years ago
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