2cos2θ−cosθ−1=0 for −180°≤θ≤180° I don't get how it is solved
1 answer:
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Answer:
Step-by-step explanation:
All the variables on the right are being multiplied together then the whole mess is being divided by 2. Let's get rid of the 2 first. The undoing of division is multiplication, so we will begin by multiplying both sides by 2 to get
Next we will move the m. The undoing of multiplication is division. So we divide both sides by m to get
The undoing of a square is to take the square root, so we will do that to both sides giving us, finally