Answer:
Step-by-step explanation:
Amari= Graph C and Solution is (-6,-2)
Bella= Graph A and Solution is (3,4)
Carl= Graph B and Solution is (0,-3)
0 solutions because the slopes are the same. The lines will never cross because they are at the exact same angle.
No, I do not agree with Joey because the lines have different slopes and will lead to the system cross which is the solution.
1st graph: y=2x-1 and y=7 solution #1= (4,7)
2nd graph: y=-2x-3 and y=1/2x solution #2= (-2,1)
3rd graph: y=x and y= -1/5+6 solution #3= (5,5)
I had this exact same assignment a few months ago, my teacher didn't use the 2nd slide but I had the 1st and 3rd slide so this should help!
28, by the way you could’ve just used a calculator
Answer:
Vertical.
Horizontal.
Diagonal
Step-by-step explanation:
8/3
divide both sides by 3 and you get x=8/3
To find the cofactor of
![A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%265%263%5C%5C-7%264%26-1%5C%5C-8%262%261%5Cend%7Barray%7D%5Cright%5D)
We cross out the Row and columns of the respective entries and find the determinant of the remaining
matrix with the alternating signs.
![Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|](https://tex.z-dn.net/?f=Ac_%7B11%7D%3D%5Cleft%7C%5Cbegin%7Barray%7D%7Bccc%7D4%26-1%5C%5C2%261%5Cend%7Barray%7D%5Cright%7C)
![Ac_{11}=4\times 1- -1\times 2](https://tex.z-dn.net/?f=Ac_%7B11%7D%3D4%5Ctimes%201-%20-1%5Ctimes%202)
![Ac_{11}=4+ 2](https://tex.z-dn.net/?f=Ac_%7B11%7D%3D4%2B%202)
![Ac_{11}=6](https://tex.z-dn.net/?f=Ac_%7B11%7D%3D6)
![Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|](https://tex.z-dn.net/?f=Ac_%7B12%7D%3D-%5Cleft%7C%5Cbegin%7Barray%7D%7Bccc%7D-7%26-1%5C%5C-8%261%5Cend%7Barray%7D%5Cright%7C)
![Ac_{12}=-(-7\times 1- -1\times -8)](https://tex.z-dn.net/?f=Ac_%7B12%7D%3D-%28-7%5Ctimes%201-%20-1%5Ctimes%20-8%29)
![Ac_{12}=-(-7- 8)](https://tex.z-dn.net/?f=Ac_%7B12%7D%3D-%28-7-%208%29)
![Ac_{12}=15](https://tex.z-dn.net/?f=Ac_%7B12%7D%3D15)
![Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|](https://tex.z-dn.net/?f=Ac_%7B21%7D%3D-%5Cleft%7C%5Cbegin%7Barray%7D%7Bccc%7D5%263%5C%5C2%261%5Cend%7Barray%7D%5Cright%7C)
![Ac_{21}=-(5\times 1- 3\times 2)](https://tex.z-dn.net/?f=Ac_%7B21%7D%3D-%285%5Ctimes%201-%203%5Ctimes%202%29)
![Ac_{21}=-(5-6)](https://tex.z-dn.net/?f=Ac_%7B21%7D%3D-%285-6%29)
![Ac_{21}=1](https://tex.z-dn.net/?f=Ac_%7B21%7D%3D1)
![A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|](https://tex.z-dn.net/?f=A_c%7B23%7D%3D-%5Cleft%7C%5Cbegin%7Barray%7D%7Bccc%7D7%265%5C%5C-8%262%5Cend%7Barray%7D%5Cright%7C)
![Ac_{23}=-(7\times 2 -8\times 5)](https://tex.z-dn.net/?f=Ac_%7B23%7D%3D-%287%5Ctimes%202%20-8%5Ctimes%205%29)
![Ac_{23}=-(14-40)](https://tex.z-dn.net/?f=Ac_%7B23%7D%3D-%2814-40%29)
![Ac_{23}=26](https://tex.z-dn.net/?f=Ac_%7B23%7D%3D26)
![A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|](https://tex.z-dn.net/?f=A_c%7B31%7D%3D%5Cleft%7C%5Cbegin%7Barray%7D%7Bccc%7D5%263%5C%5C4%26-1%5Cend%7Barray%7D%5Cright%7C)
![Ac_{31}=5\times -1 -4\times 3](https://tex.z-dn.net/?f=Ac_%7B31%7D%3D5%5Ctimes%20-1%20-4%5Ctimes%203)
![Ac_{31}=-5-12](https://tex.z-dn.net/?f=Ac_%7B31%7D%3D-5-12)
![Ac_{31}=-17](https://tex.z-dn.net/?f=Ac_%7B31%7D%3D-17)
![A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|](https://tex.z-dn.net/?f=A_c%7B33%7D%3D%5Cleft%7C%5Cbegin%7Barray%7D%7Bccc%7D7%265%5C%5C-7%264%5Cend%7Barray%7D%5Cright%7C)
![Ac_{33}=7\times 4- -7\times 5](https://tex.z-dn.net/?f=Ac_%7B33%7D%3D7%5Ctimes%204-%20-7%5Ctimes%205)
![Ac_{33}=28+35](https://tex.z-dn.net/?f=Ac_%7B33%7D%3D28%2B35)
![Ac_{33}=63](https://tex.z-dn.net/?f=Ac_%7B33%7D%3D63)
Therefore in increasing order, we have;
![Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63](https://tex.z-dn.net/?f=Ac_%7B31%7D%3D-17%2CAc_%7B21%7D%3D1%2CAc_%7B11%7D%3D6%2CAc_%7B23%7D%3D26%2CAc_%7B12%7D%3D15%2C%20Ac_%7B33%7D%3D63)