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olga55 [171]
2 years ago
14

A box with no top that has a volume of 1000 cubic inches is to be constructed from a 22 x 30-inch sheet of cardboard by cutting

squares of equal size from each corner and folding up the flaps. If one of the dimensions has to be greater than 18 inches, what size square should be cut from each corner?
a. 2.234 in
C. 1.369 in
b. 3.784 in
d. 2.758 in​
Mathematics
1 answer:
Ganezh [65]2 years ago
5 0

Answer:

a: 2.234

Step-by-step explanation:

i checked after i took the test. its right, enjoy

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Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,
torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

y=6x^2+14x

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

\frac{dy}{dx}=12x+14

We know that length of curve

s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx

We have a=-2 and b=1

Using the formula

Length of curve=s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

dt=12dx

dx=\frac{1}{12}dt

Length of curve=s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt

We know that

\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C

By using the formula

Length of curve=s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})

Length of curve=s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})

Length of curve=s=32.66

5 0
2 years ago
Someone?? Can you help me with this??
Vesna [10]

Answer:

which class question is this

3 0
2 years ago
How does the sample size affect the validity of an empirical​ argument? A. The larger the sample size the better. B. The smaller
astra-53 [7]

Answer:

A. The larger the sample size the better.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question:

We have to look at the standard error, which is:

s = \frac{\sigma}{\sqrt{n}}

This means that an increase in the sample size reduces the standard error, and thus, the larger the sample size the better, and the correct answer is given by option a.

7 0
3 years ago
Help please !! Solve -1.6r+5= -7.8
Nikolay [14]

subtract 5 from both sides. -1.6r=-5 divide both sides by-1.6. r=-5/-1.6 simp;ify-5/1.6 to 3.125. r =3.125

5 0
3 years ago
Read 2 more answers
Which of the following are corresponding angles ?
ANEK [815]

The answer is - C. R & W

4 0
3 years ago
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