Answer:100 + 3.2t = b
Step-by-step explanation: first off i would organize the data then find the varible(s) after you have all of the data organized with the verible(s) then find what number the varibles belong to. after that is done you would make
the equation which should look like 100 + 3.2t = b
Answer:
The final temperature for the day was -16 degrees.
Step-by-step explanation:
6-12= -6
-6-10= -16
25 goes into 200 exactly 8 times.
Answer:
L.H.S.
= (cos5a.sin2a-cos4a.sin3a)/ (sin5a.sin2a-cos4a.cos3a)
Multiply numerator and denominator by 2.
= 2(cos5a.sin2a - cos4a.sin3a) / 2(sin5a.sin2a - cos4a.cos3a)
= (2cos5a.sin2a - 2cos4a.sin3a)/
(2sin5a.sin2a - 2cos4a.cos3a) = [sin(5a+2a)-sin(5a-2a)-sin(4a+3a)
+sin(4a-3a)]/[cos(5a-2a)-cos(5a+2a)-sin(4a-3a) +cos(4a+3a)]
= (sina - sin3a)/(cso3a-cosa)
= (-2cos2a.sina)/(-2sin2a.sina)
= cos2a/sin2a
= cot2a
= R.H.S.
15?im not sure...but I think thats right
