Answer:
Annual demand (U) = 90.000 bags
Cost of each bag = $1.50
Inventory carrying cost per unit(C) = $1.50 × 20% = 0 30
Ordering cost per unit (O) = $15
Part A)
EOQ = 3,000
Part B)
Maximum inventory = EOQ + Safety inventory on hand
Maximum inventory = 3000 + 1000
Maximum inventory = 4.000
Part C)
Average inventory = Maximum inventory + Minimum or Safety /2
Average inventory = 4,000 + 1,000 / 2
Average inventory =2,500
Part D)
How often company order = Annual demand / EOQ
How often company order = 90,000 / 3.000
How often company order = 30
What would be the most likely place for it to advertise is: on buses and with signs on parking lots.
<h3>What is Advertisement?</h3>
Advertisement can be defined as the process of creating product awareness to attract customer so as make profit or to generate revenue.
Based on the given scenario the best place to advertise the food is on buses and with sign on parking lots since the restaurant chain has identified day commuters as it target customers doing this will help to persuade this commuter to buy the fast food product.
Inconclusion what would be the most likely place for it to advertise is: on buses and with signs on parking lots.
Learn more about advertisement here:brainly.com/question/1658517
the answer to this question is 4.70%
Answer:
Option (b) is correct.
Explanation:
Given that,
Total Overhead Cost = $477,000
Number of Units of Product XY = 72,000
Number of Units of Product M = 108,000
Total overhead allocated to Product XY using the current system:
= (Total Overhead Cost ÷ Number of units produced in total) × Number of Units of Product XY
= ($477,000 ÷ 180,000) × 72,000
= $2.65 × 72,000
= $190,800
