Remark
I'm going to interpret this equation as
D = ut + kt² The only difference is the 2.
Solution
Subtract kt² from both sides.
D - kt² = ut Now divide by u on both sides.
![\dfrac{D - kt^2}{t} = \dfrac{ut}{t}](https://tex.z-dn.net/?f=%5Cdfrac%7BD%20-%20kt%5E2%7D%7Bt%7D%20%3D%20%5Cdfrac%7But%7D%7Bt%7D)
The t's cancel out. on the right. You are left with u on the right.
![\dfrac{D - kt^2}{t} =\text{u}](https://tex.z-dn.net/?f=%5Cdfrac%7BD%20-%20kt%5E2%7D%7Bt%7D%20%3D%5Ctext%7Bu%7D)
I think it 5,158.00 round to the nearest percent
Answer:
B is correct. Your starting amount is 210$ And you're taking away 15$ each time she uses the club,x.
Step-by-step explanation:
Answer:
The linear function model the situation is b = 210 - 15x .
Option (B) is correct .
Step-by-step explanation:
Let us assume that the number of times giselle uses the club be x .
As given
giselle pays $210 in advance on her account at the athletic club.
Each time she uses the club,$15 is deducted from the account.
Let suppose that the money left after giselle uses the club x times is b .
Than the equation becomes
Money left = Amount pay in advance - Deducted amount × Number of times giselle uses the club .
Put all the values in the above
b = 210 - 15 × x
b = 210 - 15x
Therefore the linear function model the situation is b = 210 - 15x .
Option (B) is correct .
Answer:
1. the range is the biggest number minus the smallest number.
2. for IQR order the data in ascending order, find the median, calculate the median for both the upper and lower halves of the data and the IQR is the difference between the two.
3. MAD is when you find the mean then add all the data values together and divide by the amount of data you have. Lastly, do the data value minus the mean.
Step-by-step explanation:
hope this helps :)