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Len [333]
4 years ago
6

Find the value of x.

Mathematics
1 answer:
Stels [109]4 years ago
7 0

Answer:

x=136

Step-by-step explanation:

The sum of the angles inside a quadrilateral add to 360, so

79+55+110+x=360

Combine like terms

224+x=360

Subtract 224 from both sides

x=136

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Answer:

7.5 quarts

Step-by-step explanation:

2 baskets ------> make 3 quarts

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What is the sequence of 8,2,0,2,8,18​
antoniya [11.8K]

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Step-by-step explanation:

32

7 0
3 years ago
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What are the zeros of the quadratic function f(x) = 6x ^ 2 - 24x + 1 ?
ZanzabumX [31]

Answer:

x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}

Step-by-step explanation:

Let's use the quadratic formula, which states that for a quadratic of the form ax² + bc + c, the zeroes are: x=\frac{-b+\sqrt{b^2-4ac} }{2a} or x=\frac{-b-\sqrt{b^2-4ac} }{2a}.

Here, a = 6, b = -24, and c = 1. Plug these in:

x=\frac{-b+\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)+\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24+\sqrt{552} }{12}=\frac{24+2\sqrt{138} }{12} =\frac{12+\sqrt{138} }{6}

AND

x=\frac{-b-\sqrt{b^2-4ac} }{2a}

x=\frac{-(-24)-\sqrt{(-24)^2-4*6*1} }{2*6}=\frac{24-\sqrt{552} }{12}=\frac{24-2\sqrt{138} }{12} =\frac{12-\sqrt{138} }{6}

Thus, the zeroes are: x = \frac{12+\sqrt{138} }{6} and x = \frac{12-\sqrt{138} }{6}.

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Step-by-step explanation:

2x−3(3x−4)≥8

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−7x+12≥8

Step 2: Subtract 12 from both sides.

−7x+12−12≥8−12

−7x≥−4

Step 3: Divide both sides by -7.

−7x−7≥−4−7x≤47

Answer:x≤47

8 0
3 years ago
If triangle abc is congruent to triangle def what would be the coordinate of f
vova2212 [387]
Abc would be the same order with Def so the coordinate to f is C
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