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IgorLugansk [536]
3 years ago
13

In A ACE, G is the centroid and BG= 5. What is GE? C B D A F ES

Mathematics
1 answer:
sasho [114]3 years ago
7 0
I might need a little most info?
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The length of a rectangle is 3 times the width. The perimeter of the rectangle is 64 cm. Show the equation that would be used to
Kruka [31]

Answer:

64 = 2(3x + x)

Step-by-step explanation:

Perimeter of the rectangle = 64 cm

Width of the rectangle = x

Length of the rectangle = 3x

Perimeter of a rectangle = 2(length + width)

The equation is

64 = 2(3x + x)

64 = 6x + 2x

64 = 8x

x = 64/8

x = 8 cm

Width of the rectangle = x = 8 cm

Length of the rectangle = 3x

= 3(8 cm)

= 24 cm

6 0
2 years ago
Can someone please help?​
Temka [501]

your answer is 9x-6 d its pretty easy

7 0
3 years ago
Read 2 more answers
88.1-2.3f=72.46 how do you find f
V125BC [204]

Answer: f = 6.8

Step-by-step explanation:

88.1 - 2.3f = 72.46

First, subtract 88.1 from both sides

-2.3f = -15.64

Divide each side by -2.3

f = 6.8

3 0
3 years ago
Read 2 more answers
Help Please!! I'm confused about this... (you can explain or screenshot the graph and show where the points are)
saul85 [17]

Your first step is to isolate y and put it into slope-intercept form.

Then graph

See screenshots below

8 0
2 years ago
Given: X = r + 2, Y = 2r - 9, and Z = r 2 + 17r + 30. Simplify [X · Y - Z] ÷ X.
musickatia [10]

Answer: r - 24

Step-by-step explanation:

X=r+2;Y=2r-9;Z=r^2+17x+30

\frac{x*y-z}{x}

\frac{[(r+2)(2r-9)]-(r^2+17r+30)}{r+2}

\frac{(2r^2-9r+4r-18)-(r^2+17r+30)}{r+2}

\frac{(2r^2-5r-18)-(r^2+17r+30)}{r+2}

\frac{2r^2-5r-18-r^2-17r-30)}{r+2}

Combine like terms;

\frac{r^2-22r-48}{r+2}

Solve the quadratic equation;

\frac{(r-24)(r+2)}{r+2}

Simplify;

r-24

8 0
3 years ago
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