All categories

3 years ago

Find y when x = 15 if y = 6 when x= 30

Mathematics

1 answer:

Mandarinka [93]3 years ago

8 0

y=3 when x=15

this is because we can set up a ratio of when x/15 and set it equal to 6/30 and divide them, solve for x.

You might be interested in

When the county fair opened its gates, 68 people entered the fairgrounds. After one hour, there were 1.5 times as many people on

pickupchik [31]

Answer:

y=68(1.5)^(x-1)

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is the approximate circumference of the circle shown below 14.8cm

Harman [31]

Answer:

r≈2.36cm

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Andrew has already played 32 minutes on his video game today and wants to play an additional 15 minutes each of x games after sc

artcher [175]

Answer:

y = 15x+32

Step-by-step explanation:

Given

y to be the total minutes Andrew will play video games today

x is the total number of games played after school

If he wants to play an additional 15 minutes each of x games after school today, the total minutes he will use for the x games will be 15* x = (15x)minutes

We are told that he has initially spent 32minutes on video games. hence;

Total minutes Andrew used on games y = (15*x)+32

The required equation will be y = 15x+32

7 0

3 years ago

I guess I'm lacking in differential equations. I couldn't solve this question. Can you help me?

Sonja [21]

Answer:

See Explanation.

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Reciprocals

Algebra II

Log/Ln Property: $ln(\frac{a}{b} ) = ln(a) - ln(b)$

Calculus

Derivatives

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Derivative of Ln: $\frac{d}{dx} [ln(u)] = \frac{u'}{u}$

Step-by-step explanation:

Step 1: Define

$ln(\frac{2x-1}{x-1} )=t$

Step 2: Differentiate

Rewrite: $t = ln(\frac{2x-1}{x-1})$
Rewrite [Ln Properties]: $t = ln(2x-1) - ln(x - 1)$
Differentiate [Ln/Chain Rule/Basic Power Rule]: $\frac{dt}{dx} = \frac{1}{2x-1} \cdot 2 - \frac{1}{x-1} \cdot 1$
Simplify: $\frac{dt}{dx} = \frac{2}{2x-1} - \frac{1}{x-1}$
Rewrite: $\frac{dt}{dx} = \frac{2(x-1)}{(2x-1)(x-1)} - \frac{2x-1}{(2x-1)(x-1)}$
Combine: $\frac{dt}{dx} = \frac{-1}{(2x-1)(x-1)}$
Reciprocate: $\frac{dx}{dt} = -(2x-1)(x-1)$
Distribute: $\frac{dx}{dt} = (1-2x)(x-1)$