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satela [25.4K]
3 years ago
9

I need help with this. I don’t understand how to do this

Mathematics
1 answer:
Stolb23 [73]3 years ago
7 0

Answer:

Read below ( Equal Square roots and non equal square roots)

Step-by-step explanation:

Finding square roots of of numbers that aren't perfect squares without a calculator.

Example: Calculate the square root of 10 ( ) to 2 decimal places.

Find the two perfect square numbers it lies between.

Divide 10 by 3. ...

Average 3.33 and 3. ( ...

Repeat step 2: 10/3.1667 = 3.1579.

A square root of a number is a value that, when multiplied by itself, gives the number. Example: 4 × 4 = 16, so a square root of 16 is 4. ... The symbol is √ which always means the positive square root.

If you still need help, I recommend you search this up.

Understanding square roots (video)

<h2>Good Luck</h2>
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Any number that can be written as a fraction is?
Roman55 [17]
Every whole number is a rational number because whole numbers can be written as fractions.
3 0
3 years ago
I need help I’ll mark u as brainlest
Minchanka [31]

Answer:

V = 64 in^3

Step-by-step explanation:

The volume of a cube is given by

V = s^3 where s is the side length

V = 4^3

V = 64 in^3

8 0
3 years ago
Read 2 more answers
How many solutions exist for the given equation? <br><br> 3(x-2) =22 -x
kenny6666 [7]

Answer:

one solution

Step-by-step explanation:

3(x-2) =22 -x

Distribute

3x - 6 = 22-x

Add x to each side

3x+x-6 = 22-x+x

4x+6 = 22

Subtract 6 from each side

4x+6-6 = 22-6

4x= 16

Divide by 4

4x/4 = 16/4

x=4

There is one solution

6 0
2 years ago
Which is greater .13 or .3
Ray Of Light [21]

Answer:

.3 is greater.

Step-by-step explanation:

.13

.3 or .30

These are the same, and obviously .30 is larger than .13.

4 0
3 years ago
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Reduced form of 2ab^2-a^2 b^2/5
Ket [755]

Answer:

2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}

Step-by-step explanation:

Given the expression

2ab^2-\frac{a^2b^2}{5}

\mathrm{Convert\:element\:to\:fraction}:\quad \:2ab^2=\frac{2ab^25}{5}

2ab^2-\frac{a^2b^2}{5}=\frac{2ab^2\cdot \:5}{5}-\frac{a^2b^2}{5}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

                 =\frac{2ab^2\cdot \:5-a^2b^2}{5}

                 =\frac{10ab^2-a^2b^2}{5}

Thus,

2ab^2-\frac{a^2b^2}{5}=\frac{10ab^2-a^2b^2}{5}

7 0
3 years ago
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