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Nookie1986 [14]
3 years ago
10

Define the term perfect square.

Mathematics
1 answer:
Hoochie [10]3 years ago
4 0
The term perfect square means that the square root of the number is a whole number. \sqrt{1}= 1  
\sqrt{4}= 2 
 \sqrt{9}= 3\\  
\sqrt{16}= 4 \\
 \sqrt{25}= 5\\
 \sqrt{36}= 6\\   
And\ so\ on.
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In the order of operations, expressions inside parentheses are evaluated before exponents.
Ivanshal [37]
Yes because in PEMDAS, the P is parentheses and E is exponents which means P is first. So, true.
4 0
3 years ago
PLEASE HELP
Andru [333]

ANSWER

q =  - 7p

EXPLANATION

The constant difference of p values is

4-2=2

The constant difference of the 'q' values is

-28--14=-14

The function is of the form:

q = m(p  - p_1) + q_1

where

m =  \frac{change \: in \:q }{change \: in \: p}

m =  \frac{ - 14}{2}  =  - 7

We plug in the values to get;

q =  - 7(p  - 2) +  - 14

Expand:

q =  - 7p   + 14+  - 14

Simplify:

q =  - 7p

8 0
3 years ago
Dropping less than two inches per mile after emerging from the​ mountains, a river drains into the ocean. One​ day's discharge a
Tanya [424]

Answer:

dont know sorry

Step-by-step explanation:

4 0
3 years ago
1/2(x-4)=1/3(x+2) <br> Helppp plsss will give brainilist
melamori03 [73]

Answer:

x= 16

Step-by-step explanation:

combine multiplied terms into  a single fraction

\frac{1}{2} (x-4)=\frac{1}{3} (x+2)

\frac{1(x-4)}{2} =\frac{1}{3} (x+2)

Multiply by 1

\frac{1(x-4)}{2} =\frac{1}{3} (x+2)

\frac{x-4}{2} =\frac{1}{3} (x+2)

Combine multiplied term into a single fraction

\frac{x-4}{2} =\frac{1(x+2)}{3}

Multiply by 1

\frac{x-4}{2} =\frac{x+2}{3}

Multiply all terms by the same value to eliminate fraction denominators

6*\frac{x-4}{2} 6(\frac{x+2}{3} )

cancel multiplied terms that are in the denominator

3(x-4)=2(x-2)

Distribute

3x-12=2(x+2)

Distribute

3x-12=2x+4

Add 12 to both sides of the equation

3x-12+12=2x+4+12

Simplify

3x=2x+16

Subtract 2x from both sides of the equation

3x=2x=2x+16-2x

Simplify

x=16

8 0
3 years ago
Karissa says that to represent the expression - 7 - (- 9) on number line, she should start at 7 and move units to the IN correct
Sholpan [36]

Answer:

No

Step-by-step explanation:

Should start at -7 and move 9 units towards right (in the positive direction).

Should stop at 2

8 0
3 years ago
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