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TEA [102]
3 years ago
9

HELP PLEASE ILL GIVE THE BRAINLIEST TO WHOEVER ANSWERS CORRECTLY!!!

Mathematics
2 answers:
Sav [38]3 years ago
8 0
The answer to your question is D
drek231 [11]3 years ago
6 0

Answer:

D. translation, yes

Step-by-step explanation:

A is out because the shapes are congruent, and if the figure was reflected, it would have been closer to the y-axis. It is the same with B, if the figure was dilated, the second figure would have been similar but not congruent. C is out because the figure is still facing the same direction.

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Please help!!!! I obviously don’t need 10,11,and 12
tatyana61 [14]
For 1-5, you add up both angles that are stated and then subtract that number from 180 to get the missing angle.
For 6, the top angle is equal to 40 since half of it equals 20. The other 2 angles are equivalent, so we subtract 40 from 180 and then divide that number by 2 to get your answer.
For 7, you see two triangles on one. The first triangle has the angles of 60 and 60, and since a triangles angles add up to 180, we add both angles and subtract it from 180 to get that side. Since a straight angle is also equal to 180 degrees, the answer you just got and the answer you’re looking for are supplementary angles. So, you subtract that answer from 180 to get your answer.
For 8, you do the same thing with supplementary angles. Since the straight lines is equal to 180 degrees, we subtract 144 from it to get your answer.
For 9, we do the same thing that we did with number 7. The first triangles sides are 40 and 70, so we add those together and subtract it from 180 to get the missing side. That side and the one that you’re looking for are supplementary angles, so you subtract that side from 180 to get your answer.
3 0
3 years ago
∆ ABC is isosceles with AB= AC= 7.5cm and BC= 0 cm .the height AD from A to BC, is 6cm . find the area of ∆ ABC what will be the
lora16 [44]

I have attached an image of the triangle.

BC = 9 cm

Answer:

CE = 7.2 cm

Step-by-step explanation:

In the attached triangle, we see that;

AB = AC = 7.5cm

BC = 9 cm

AD = 6cm

BC = 9cm

Formula for area of triangle is given as;

A = ½bh

Where b is base and h is height.

For the ∆ ABC with BC as base,

Area = ½ × 9 × 6 = 27 m²

Similarly, For ∆ ABC with AB as base,

Area = ½ × 7.5 × CE

Now, area from earlier is 27 cm²

Thus;

½ × 7.5 × CE = 27

Multiply both sides by 2 to get;

7.5CE = 54

CE = 54/7.5

CE = 7.2 cm

3 0
3 years ago
Joseph needs to calculate how much grass seed he needs to cover his lawn. A diagram of his lawn is shown below. One pound of see
viktelen [127]
L x W = Area
40 x 15 = 600 square ft
So you would need 6 bags of feed
600/ 100 = 6
4 0
3 years ago
20 points!!!
Ghella [55]
Area of semi circle: you know the radius is 5. 5^2 * pi = 25pi/2 = 12.5pi
For triangle: bh/2 = (10 * 10)/2 = 50
Add them together: 12.5pi + 50
12.5pi = 39.25
39.25 + 50 = 89.25
It’s closest to D
8 0
3 years ago
Read 2 more answers
You work at a pioneer historical site. On this site you have handcarts. One cart has a handle that connects to the center of the
Gelneren [198K]

Answer:

a)  see below

b)  radius = 16.4 in (1 d.p.)

c)  18°. Yes contents will remain. No, handle will not rest on the ground.

d)  Yes contents would spill.  Max height of handle = 32.8 in (1 d.p.)

Step-by-step explanation:

<u>Part a</u>

A chord is a <u>line segment</u> with endpoints on the <u>circumference</u> of the circle.  

The diameter is a <u>chord</u> that passes through the center of a circle.

Therefore, the spokes passing through the center of the wheel are congruent chords.

The spokes on the wheel represent the radii of the circle.  Spokes on a wheel are usually evenly spaced, therefore the congruent central angles are the angles formed when two spokes meet at the center of the wheel.

<u>Part b</u>

The <u>tangent</u> of a circle is always <u>perpendicular</u> to the <u>radius</u>.

The tangent to the wheel touches the wheel at point B on the diagram.  The radius is at a right angle to this tangent.  Therefore, we can model this as a right triangle and use the <u>tan trigonometric ratio</u> to calculate the radius of the wheel (see attached diagram 1).

\sf \tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

Given:

  • \theta = 20°
  • O = radius (r)
  • A = 45 in

Substituting the given values into the tan trig ratio:

\implies \sf \tan(20^{\circ})=\dfrac{r}{45}

\implies \sf r=45\tan(20^{\circ})

\implies \sf r=16.37866054...

Therefore, the radius is 16.4 in (1 d.p.).

<u>Part c</u>

The measure of an angle formed by a secant and a tangent from a point outside the circle is <u>half the difference</u> of the measures of the <u>intercepted arcs</u>.

If the measure of the arc AB was changed to 72°, then the other intercepted arc would be 180° - 72° = 108° (since AC is the diameter).

\implies \sf new\: angle=\dfrac{108^{\circ}-72^{\circ}}{2}=18^{\circ}

As the handle of the cart needs to be no more than 20° with the ground for the contents not to spill out, the contents will remain in the handcart at an angle of 18°.

The handle will not rest of the ground (see attached diagram 2).

<u>Part d</u>

This can be modeled as a right triangle (see diagram 3), with:

  • height = (48 - r) in
  • hypotenuse ≈ 48 in

Use the sin trig ratio to find the angle the handle makes with the horizontal:

\implies \sf \sin (\theta)=\dfrac{O}{H}

\implies \sf \sin (\theta)=\dfrac{48-r}{48}

\implies \sf \sin (\theta)=\dfrac{48-45\tan(20^{\circ})}{48}

\implies \theta = 41.2^{\circ}\:\sf(1\:d.p.)

As 41.2° > 20° the contents will spill out the back.

To find the <u>maximum height</u> of the handle from the ground before the contents start spilling out, find the <u>height from center of the wheel</u> (setting the angle to its maximum of 20°):

\implies \sin(20^{\circ})=\dfrac{h}{48}

\implies h=48\sin(20^{\circ})

Then add it to the radius:

\implies \sf max\:height=48\sin(20^{\circ})+45\tan(20^{\circ})=32.8\:in\:(1\:d.p.)

(see diagram 4)

------------------------------------------------------------------------------------------

<u>Circle Theorem vocabulary</u>

<u>Secant</u>: a straight line that intersects a circle at two points.

<u>Arc</u>: the curve between two points on the circumference of a circle

<u>Intercepted arc</u>: the curve between the two points where two chords or line segments (that meet at one point on the other side of the circle) intercept the circumference of a circle.

<u>Tangent</u>: a straight line that touches a circle at only one point.

7 0
2 years ago
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