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Mathematics

2 answers:

Sav [38]3 years ago

8 0

The answer to your question is D

drek231 [11]3 years ago

6 0

Answer:

D. translation, yes

Step-by-step explanation:

A is out because the shapes are congruent, and if the figure was reflected, it would have been closer to the y-axis. It is the same with B, if the figure was dilated, the second figure would have been similar but not congruent. C is out because the figure is still facing the same direction.

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35 into binary number

vodka [1.7K]

Answer:

35 in binary is 100011.

Step-by-step explanation:

To find decimal to binary equivalent, divide 35 successively by 2 until the quotient becomes 0.

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3 years ago

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In a theater, there are 4 long rows of chairs,each with an equal number of chairs There are 5 ahort rows of chairs,each with an

Hoochie [10]

There are 4 long rows and 5 short rows in the theater. x represents the number of chairs in each long row and y represents the number of chairs in each short row.

So, total number of chairs in 4 long rows= 4x
Total number of chairs in 5 short rows = 5y
Total number of chairs in the theater on a normal day = 4x + 5y

When 2 chairs are added to each long row, the number of chairs will change to (x+2).
So, total number of chairs in 4 long rows will be = 4(x+2)

When 3 chairs are added to each short row, the number of chairs will change to (y+3)
So, total number of chairs in 5 short rows will be = 5(y+3)

Thus, total number of chairs in the theater in rush day = 4(x+2) + 5(y+3)
= 4x + 8 + 5y + 15
= 4x + 5y + 23

Thus we can say the number of chairs increase by 23 as compared to a normal day.

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3 years ago

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This a 2 part question. F(x) is the graph shown.

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Suppose f(x) is an even function. The range of g(x) = -3f(2x) is [-9, 3].

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A survey of 35 people was conducted to compare their self-reported height to their actual height. The difference between reporte

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Answer:

The test statistic is t = 3.36.

Step-by-step explanation:

You're testing the claim that the mean difference is greater than 0.7.

At the null hypothesis, we test if the mean difference is of 0.7 or less, that is:

$H_0: \mu \leq 0.7$

At the alternate hypothesis, we test if the mean difference is greater than 0.7, that is:

$H_1: \mu > 0.7$

The test statistic is:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.