The area of wood needed for the frame is 5. 5 + 106 square inches. Option A
<h3>How to determine the area</h3>
The amount of wood needed for the window frame will be equal to area of window frame.
It is important to note that the upper part of window is semicircle
Area of the upper part = π ![\frac{R^2 - r^2}{2}](https://tex.z-dn.net/?f=%5Cfrac%7BR%5E2%20-%20r%5E2%7D%7B2%7D)
where,
R = Outer radius,
r = Inner radius.
Area of upper part = π × ![\frac{6^2 - 5^2}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B6%5E2%20-%205%5E2%7D%7B2%7D)
Area of upper part = 11π/2
Area of upper part = 5. 5π
To find the area of the lower part, it is important to note that the area of lower part of frame will be area of 3 different rectangles. Two are the same rectangles with length 48 inches and width 1 inch and one rectangle with length 10 inches (12-2) and width 1 inch.
Area of lower part = 2 × 48 × 1 + 10 × 1
Area of lower part = 96 + 10
Area of lower part = 106 inches
Thus, the area of wood needed for the frame is 5. 5 + 106 square inches. Option A
Learn more about area of a rectangle here:
brainly.com/question/25292087
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Answer:
The
of the player is ![L_{ACL} = 56.82 \ mm](https://tex.z-dn.net/?f=L_%7BACL%7D%20%20%3D%20%2056.82%20%5C%20mm)
Step-by-step explanation:
From the question we are told that
The relationship between the length
to the height is
![L_{ACL} = 0.04606h - (41.29 \ mm)](https://tex.z-dn.net/?f=L_%7BACL%7D%20%3D%20%200.04606h%20-%20%2841.29%20%5C%20mm%29)
The height of the basketball player is ![h = 2.13 \ m = 2130 \ mm](https://tex.z-dn.net/?f=h%20%3D%20%202.13%20%5C%20m%20%3D%202130%20%5C%20mm)
Substituting the value of height of the basket ball player in to the model we have the
of the player is
![L_{ACL} = 0.04606 (2130) - (41.29 ) \ mm](https://tex.z-dn.net/?f=L_%7BACL%7D%20%20%3D%20%200.04606%20%282130%29%20-%20%2841.29%20%29%20%5C%20mm)
![L_{ACL} = 56.82 \ mm](https://tex.z-dn.net/?f=L_%7BACL%7D%20%20%3D%20%2056.82%20%5C%20mm)
So therfor from 19-6x to 2+4x the diffence if the same as the diffence between 2+4x an d6x+1
so (2+4x)-(19-6x)=(6x+1)-(2+4x)
add like terms
2+4x-19+6x=6x+1-2-4x
10x-17=2x-1
add 17 to both sdies
10x-2x+16
subtract 2x form both sdies
8x=16
divide boht sdie syb 8
x=2
x=2
therfor the terms are
7, 10, 13
Answer:
y = x² - 3x - 28
Step-by-step explanation:
given a parabola with x- intercepts x = a and x = b , then
(x - a) and (x - b) are the corresponding factors and the equation is the product of its factors
y = (x - a)(x - b)
here the x- intercepts are x = - 4 and x = 7 , then the factors are
(x - (- 4)) and (x - 7) , that is (x + 4) and (x - 7) , then
y = (x + 4)(x - 7) ← expand using FOIL , then
y = x² - 3x - 28 ← in standard form
If there is a 506,211 pound whale on a scale and you add another whale of 424,809 pounds on the scale how much would they both weigh?