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creativ13 [48]
2 years ago
14

How do i express .194 as a fraction when the 9 and 4 are repeating?

Mathematics
2 answers:
Helga [31]2 years ago
8 0
If 9 and 4 are repeating in .194 it should be
__
.194
atroni [7]2 years ago
7 0
It would be 97/500 if you do it on a calculator, but that’s the only way I’m aware of how to do it.
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Brenda’s bank offers car financing for 3, 4 or 5 years. If brenda chooses 5-year financing, how many monthly payments will she h
klemol [59]
The number of monthly payments Brenda will have will be given by:
Number of payments=[Number of years]×[number of months]
Number of years=5
Number of months=12
hence
# Payments=5*12=60 monthly payments
7 0
3 years ago
Justin's pays is represented by this line graph.
Mashutka [201]

Answer:

He is been paid $7 per hour

Step-by-step explanation:

140dollars/ 20 hours

7 0
2 years ago
Read 2 more answers
Tell whether the given value is a solution of the inequality.<br> x + 1 &gt; 10; x = 9
Oliga [24]

Answer:

given x+1 > 10,

x > 10 - 1

x > 9

which means x MUST BE more than 9 , which also means 9 isnt included in the inequality therefore x = 9 is not a solution.

6 0
2 years ago
The question is in the picture. Plz helppp it is due tonight
Mkey [24]

Answer:

Step-by-step explanation:

We're given one equation, we have to find the other equation and solve each for 200, and whichever has the lower x is the winner

for Jayden we are given

(0, 48), (1, 56), (2, 64), (3, 72), (4, 80)

This looks to be a line. The y values are each separated by a common difference

We can use two points to describe the line

m = \frac{y_2-y_1}{x_2-x_1} = \frac{80-48}{4-0} = \frac{32}{4} = 8\\  K = 8m + b\\48 = 8(0) + b\\b = 48\\so\\K = 8m + 48

Now we can set both K = 8m + 48 and K = m^2 + 10 equal to 200

200 = 8m + 48\\152 = 8m \\m = \frac{152}{8} = 19

200 = m^2 + 10\\m^2 = 190\\m = \sqrt{190} = 13.784

Keiko's blog will reach 200 subscribers fastest.

7 0
2 years ago
A player is randomly dealt a sequence of 13 cards from a deck of 52-cards. All sequences of 13 cards are equally likely. In an e
VikaD [51]

Answer:

Answer is 1/13

Step-by-step explanation:

Here we are not intimated about the first (01) twelve (12) cards that are shown, the probability that the thirteenth (13) card dealt is a King, if this is the same as the probability that the (01) first card shown, or in fact any particular card dealt is a King, then it equals:

=4/52

=1/13 ANS

5 0
3 years ago
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