Hello from MrBillDoesMath!
Answer:
31a. 2 real roots
31b 2 complex roots
Discussion:
31a.
2x^2 + 3x - 6 = 0
Using standard quadratic notation, the above equation has a = 2, b = 3 and c = -6. The discriminant is given by b^2 - 4ac, which is
3^2 - 4*2*(-6) = 9 + 48 = 57 > 0, so the quadratic has 2 real roots
31b.
The equation is equivalent to 16x^2 + 10x +3 = 0. Its discriminant is
10^2 - 4 * (16) * (3) = 100 - 192 = -92 so this equation has two complex roots
Regards,
MrB
Answer:
Machine A=504 parts in 12h
Machine B=564 parts in 10 h
Step-by-step explanation:
please find the attached picture for steps
Answer:joe
Step-by-step explanation:
We have that
solution is
x <-10 or x>=25
for
x < -10
the solution is the interval (-∞, -10)
and
for
x>=25
the solution is the interval [25,∞)
therefore
the solution for
x <-10 or x>=25
is
(-∞, -10) ∪ [25,∞)
<span>the solution is any value of x less than -10 or greater than or equal to 25</span>
x-intercept = (15, 0) y-intercept = (0, 3)
slope (m) = (y₂ - y₁)/(x₂ - x₁) = (0 - 3)/(15 - 0) = -3/15 = -1/5
Point-Slope formula: y - y₁ = m(x - x₁) ; where (x₁, y₁) is one of the given points
y - 0 = (-1/5)(x - 15)
-5y = x - 15
x + 5y = 15
Answer: x + 5y = 15
