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3 years ago

How can you use a coordinate plane to draw a polygon?

Mathematics

1 answer:

Naily [24]3 years ago

5 0

Answer:

Question says to draw a polygon with the given conditions in a coordinate plane. It is talking about Rectangle with perimeter of 20 units.

So we can use formula of perimeter of rectangel to find it's possible dimensions.

We knwo that perimeter of the rectangle is given by 2(L+W)

where L is lenght and W is width.

Given perimeter is 20 so we get:

2(L+W)=20

L+W=10

L=10-W

So basically we can use any number for W which can be from 0 to 10 as side length can't be negative.

Let W=4

Then L=10-W=10-4=6

Hence we just have to draw a rectangle having length 6 and width 4.

So the final answer will be picture in the attached graph.

Step-by-step explanation:

pls mark it as Brainliest answer ❤

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Write this number in standard form.<br><br> four billion and six tenths

Tomtit [17]

4.0006 I think it is?

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3 years ago

Tricia and Melanie are both saving money for their summer vacations. They both began saving at the same time. Tricia started wit

fomenos

Answer:

Approximately 2 months

Step-by-step explanation:

Tricia: f(d) = 5.15m + 10.25

Melanie: f(d) = 10.25m

f(d) is the total savings altogether

m is the amount of months

5.15(2) + 10.25 = 20.55

10.25(2) = 20.50

They will have the same amount of savings in approximately 2 months

1.990291 is the actual time (in months) they will be the same

4 0

3 years ago

Read 2 more answers

Simplify <img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B6%5E4%7D" id="TexFormula1" title="\sqrt[4]{6^4}" alt="\sqrt[4]{6^4}"

Tamiku [17]

Answer:

Step-by-step explanation:

We can rewrite the expression as

(6^4) ^ (1/4)

We know that a^ b^c = a^ ( b*c)

6^4 ^ (1/4)

6 ^ ( 4*1/4)

5 0

3 years ago

Read 2 more answers

Use algebra to solve 3x+4 = 1/x<br> The exact solutions are x=<br> Х

skad [1K]

Answer:

Ignore the A before the ±, it wouldn't let me type it correctly.

$x=\frac{2±\sqrt{7} }{3}$

Step-by-step explanation:

3x + 4 = 1 ÷ x

3x + 4 - 4 = 1 ÷ x - 4

3x = 1 ÷ x - 4

$3x=\frac{1}{x} +\frac{x(-4)}{x}$

$3x=\frac{1+x(-4)}{x}$

$3x=\frac{1-4x}{x}$

$x(3x)=x(\frac{1-4x}{x})$

x · 3x = - 4x + 1

3x² = - 4x + 1

3x² - (- 4x + 1) = 0

3x² + 4x - 1 = 0

Ignore the A before the ±, it wouldn't let me type it correctly.

$x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}$

a = 3

b = 4

c = - 1

$x=\frac{-4±\sqrt{4^{2}-4((3)(-1)) } }{2(3)}$

$x=\frac{-4±\sqrt{16-4((3)(-1)) } }{2(3)}$

$x=\frac{-4±\sqrt{16+12 } }{2(3)}$

$x=\frac{-4±\sqrt{28 } }{2(3)}$

$x=\frac{-4±\sqrt{(2)(14) } }{2(3)}$

$x=\frac{-4±\sqrt{(2)(2)(7) } }{2(3)}$

$x=\frac{-4±\sqrt{2 } \sqrt{2}\sqrt{7} }{2(3)}$

$x=\frac{-4±2\sqrt{7} }{2(3)}$

$x=\frac{-4±2\sqrt{7} }{6}$

Two separate equations

$x=\frac{-4+2\sqrt{7} }{6}$

$x=\frac{2+\sqrt{7} }{3}$

$x=\frac{-4-2\sqrt{7} }{6}$

$x=\frac{2-\sqrt{7} }{3}$

7 0

3 years ago

Which set of ordered pairs (x, y) could represent a linear function?

Zanzabum

The correct answer is D

3 0

3 years ago