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3 years ago

Is the line x=-3 parallel to the line y=1/3

Mathematics

1 answer:

Zina [86]3 years ago

8 0

Answer:

No, The line x = 3 is not parallel to the line y = 1/3

Step-by-step explanation:

Here's What the graph looks like on Demos graphing calculator.

High Hopes^^

Barry-

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mixas84 [53]

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3 years ago

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adoni [48]

Answer:

Step-by-step explanation:

5x3 is 15

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3 years ago

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Initially, there are 40 grams of A and 50 grams of B, and for each gram of B, 2 grams of A is used. It is observed that 15 grams

hram777 [196]

Answer:

$X(16)=25.71grams$

Step-by-step explanation:

let $X(t)$ denote grams of $C$ formed in $t$ mins.

For $X grams$ of $C$ we have:

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Amounts of A,B remaining at any given time is expressed as:

$40-\frac{2}{3}Xg$ of A and $50-\frac{1}{3}Xg$ of B

Rate at which C is formed satisfies:

$\frac{dX}{dt} \infty(40-\frac{2}{3}X)(50-\frac{1}{3}X)->\frac{dX}{dt}=k(90-X)\\\therefore \frac{dX}{(90-X)^2}=kdt->\int{\frac{dX}{(90-X)^2}} \, =\int {k} \, dt \\\therefore \frac{1}{90-X}=kt+c->90-X=\frac{1}{kt+c}\\\\X(t)=90-\frac{1}{kt+c}$

Apply the initial condition, $X(0)=0$ ,to the expression above

$0=90-\frac{1}{c} \ \ ->c=\frac{1}{90}\\\therefore\\X(t)=90-\frac{1}{kt+\frac{1}{90}} \ \ ->X(t)=90-\frac{90}{90kt+c}$

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Substitute in X(t) to get

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3 years ago

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Afina-wow [57]

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netineya [11]

Answer:

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Step-by-step explanation:

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