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Natali5045456 [20]
3 years ago
13

What Is 45% Of 90? Please Help!!

Mathematics
2 answers:
ale4655 [162]3 years ago
5 0

Answer: 40 and 1/2

Step-by-step explanation:

=>45% of 90

=>45/100×90

=>9/20×90

=>9/2×9

=>81/2

=>40 and 1/2

lukranit [14]3 years ago
4 0

Answer:gsdgsdfgsdfgsdggsdfgdgdgsdgdfg

Step-by-step explanation:sdfgsdfgdsfgasdfashaderwrwetw

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Harry is trying to solve the equation y = 2x^2 − x − 6 using the quadratic formula. He has made an error in one of the steps bel
Bond [772]
He made a mistake in step #2. It seemed to be a trivial mistake because it involved signs, but it still had a great impact. Since step#2, his solution was already wrong.

Instead of
(-1)²-4(2)(-6) = 1 + 48 = 49

What he did is
(-1)²-4(2)(-6) = -1 + 48 = 47
4 0
2 years ago
If you have 66 data observations in a sample, how many classes (bins) does the sturges' rule recommend for you to construct a fr
Iteru [2.4K]

According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7

Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.

Given,

n = 66

We know that,

According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:

k=1+log_{2} n

Here, n is equal to 66 and by substituting the value to the equation we get:

k=1+log_{2} (66)

k = 7.0444

k ≈ 7

Learn more about Sturge's rule here: brainly.com/question/28184369

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8 0
1 year ago
What is 5/8 x 1/10 im dumb plz help me ;-;
andrezito [222]
The answer should be: 5/8 x 1/10 = 1/16.
3 0
3 years ago
How do I solve 3x(4x-15)
inna [77]
3x(4x - 15) < Given
12x^2 - 45x < Distributive law of property

By the way, you are simplifying not solving. You solve equations and simplify expressions.

7 0
3 years ago
Find the number of steel ball bearings, each of diameter 0.7 cm, that can be made from 1kg of steel, given that 1cm cubed of ste
dimulka [17.4K]

Answer:

Ball Bearing Volume = (4 / 3) * PI * radius ^3

Volume = (4 / 3) * 3.14159265 * (.35)^3

Volume = (4 / 3) * 3.14159265 * 0.042875

Volume = 0.17959438 cc

1 cc of steel = 7.8 g

Volume of 1 kg of steel = 1,000 cc / 7.8 g per cc

1 kg = 128.205 cc

Number of ball bearings we can make = 128.205 / 0.17959438

Equals 713.86

Step-by-step explanation:

7 0
3 years ago
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