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3 years ago

How do I do this I really need to know!

Mathematics

1 answer:

Nostrana [21]3 years ago

6 0

Answer:

Step-by-step explanation:

I'm doing seven.

x = -2

y = 2^(-2 -1) + 2

y = 2^(-3) + 2

y = 1/2^3 + 2

y = 1/8 + 2

y = 2.125 which is a guess on the graph.

x = - 1

y = (2)^(-1 -1) + 2

y = (2)^-2 + 2

y = 1/4 + 2

y = 2.25

x = 0

y = 2^(0 - 1) + 2

y = 2^(-1) + 2

y = 1/2 + 2

y = 2.5

x = 1

y = 2^(1 - 1) + 2

y = 2^0 + 2 If the power of a number = 0 then the result = 1. The only exception to that is 0^0

y = 1 + 2

y = 3

Eight

x = -1

y = (1/2)^(-1 + 1) + 2

y = 1 + 2

y = 3

x = 0

y = (1/2)^(0 - 1) + 2

y = (1/2)^-1 + 2 Turn the 1/2 upside down

y = 2 + 2

y = 4

x = 1

y = (1/2)^(1 + 1) + 2

y = (1/2)^2 + 2

y = 1/4 + 2

y = 2.25

x = 2

y = (1/2)^(2 + 1) + 2

y = (1/2)^3 + 2

y = 1/8 + 2

y = 2.125

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Step-by-step explanation:

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3 years ago

4. Use the process outlined in the lesson to approximate the number 2√3. Use the approximation √3 ≈ 1.732 050 8.

jeka57 [31]

Answer:

sequence of five intervals

(1) 2 < $2^{\sqrt{3} }$ < $2^{2}$

(2) $2^{1.7}$ < $2^{\sqrt{3} }$ < $2^{1.8}$

(3) $2^{1.73}$ < $2^{\sqrt{3} }$ < $2^{1.74}$

(4) $2^{1.732}$ < $2^{\sqrt{3} }$ < $2^{1.733}$

(5) $2^{1.7320}$ < $2^{\sqrt{3} }$ < $2^{1.7321}$

Step-by-step explanation:

as per question given data

√3 ≈ 1.732 050 8

to find out

sequence of five intervals

solution

as we have given that √3 value that is here

√3 ≈ 1.732 050 8 ........................1

when we find $2^{\sqrt{3} }$ ................2

put here √3 value in equation number 2

we get $2^{\sqrt{3} }$ that is 3.322

sequence of five intervals

(1) 2 < $2^{\sqrt{3} }$ < $2^{2}$

(2) $2^{1.7}$ < $2^{\sqrt{3} }$ < $2^{1.8}$

(3) $2^{1.73}$ < $2^{\sqrt{3} }$ < $2^{1.74}$

(4) $2^{1.732}$ < $2^{\sqrt{3} }$ < $2^{1.733}$

(5) $2^{1.7320}$ < $2^{\sqrt{3} }$ < $2^{1.7321}$

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