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Karo-lina-s [1.5K]
3 years ago
7

How do I do this I really need to know!

Mathematics
1 answer:
Nostrana [21]3 years ago
6 0

Answer:

Step-by-step explanation:

I'm doing seven.

<em><u>x = -2</u></em>

y = 2^(-2 -1) + 2

y = 2^(-3) + 2

y = 1/2^3 + 2

y = 1/8 + 2

y = 2.125 which is a guess on the graph.

<em><u>x = - 1</u></em>

y = (2)^(-1 -1) + 2

y = (2)^-2 + 2

y = 1/4 + 2

y = 2.25

x = 0

y = 2^(0 - 1) + 2

y = 2^(-1) + 2

y = 1/2 + 2

y = 2.5

<em><u>x = 1</u></em>

y = 2^(1 - 1) + 2

y = 2^0 + 2           If the power of a number = 0 then the result = 1. The only exception to that is 0^0

y = 1 + 2

y = 3

Eight

<em><u>x = -1</u></em>

y = (1/2)^(-1 + 1) + 2

y = 1 + 2

y = 3

<em><u>x = 0</u></em>

y = (1/2)^(0 - 1) + 2

y = (1/2)^-1 + 2             Turn the 1/2 upside down

y = 2 + 2

y = 4

<em><u>x = 1</u></em>

y = (1/2)^(1 + 1) + 2

y = (1/2)^2 + 2

y = 1/4 + 2

y = 2.25

<em><u>x = 2</u></em>

y = (1/2)^(2 + 1) + 2

y = (1/2)^3 + 2

y = 1/8 + 2

y = 2.125

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What is the rate of change of y with respect to x for this function?​
lilavasa [31]

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Given the function: y=f(x) = 3x+2

when x=-2 at the beginning of the interval [-2, 5],

then;

y = 3x+2 begins at

y= 3(-2)+2 = -6+2= -4.

and

when x=5 at the end of the interval [-2, 5],

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So,

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=

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Step-by-step explanation:

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3 years ago
Use the quadratic formula to solve x2 + 2x - 120 = 0. Think about what other method could also be used to solve this equation. a
pshichka [43]

Answer:

x = 10 , -12

Step-by-step explanation:

Solution:-

- The given quadratic equation is to be solved using the quadratic formula. The general form of a quadratic equation is:

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Where, [ a , b and c are constants ]

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                           x = \frac{-b+/-\sqrt{b^2 - 4*a*c} }{2a}

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Where, a = 1 , b = 2 , c = -120

- Solve using quadratic formula:

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7 0
3 years ago
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