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3 years ago

Hi guys! I need to show all work for this. Your answers are much appreciated! 5 divided by 0.8

Mathematics

1 answer:

kirill [66]3 years ago

8 0

The correct answer is 6.25

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which of the following statements is true? a. the radius of a circle is twice its diameter b. to find the diameter of a circle,

Bess [88]

Answer:

Statement B, C, E are correct

<u>Solution:</u>

We have to find the true statements

We know that,

To find the diameter of a circle, multiply its radius by two

Thus statement E is correct

Also,

To find the diameter of a circle, divide its circumference by π

Thus statement B is correct

circumference of a circle is obtained by multiplying diameter with pi

The circumference of a circle is greater than its diameter

Thus, Statement C is correct

4 0

3 years ago

Read 2 more answers

Express the ratio 14 inches to 3 feet as a fraction in simplest form

artcher [175]

The answer is gonna be 14:36

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3 years ago

Jay had to paint part of the outside of his house he spent 7 hours painting one side and 12 hours painting another how long did

jolli1 [7]

Another 12 hours to get it going

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3 years ago

there is sales tax of $9.00 on an item t that cost 120.00 before tax. the sales tax on a different item is 19.05. how much does

Luda [366]

254 how you do this is 9/120 which equals .075 and then 19.05/.075 which equals 254

4 0

4 years ago

Suppose that 10% of all homeowners in an earthquake-prone area of California are insured against earthquake damage. Four homeown

guapka [62]

Remainder of question:

Find the probability distribution of x

Answer:

The random variable x is defined as: X = {0, 1, 2, 3, 4}

The probability distribution of X:

P(X = 0) = 0.656

P(X = 1) = 0.2916

P(X= 2) = 0.0486

P(X=3) = 0.0036

P(X = 4) = 0.0001

Step-by-step explanation:

Sample size, n = 4

Random variable, X = {0, 1, 2, 3, 4}

10% (0.1) of the homeowners are insured against earthquake, p = 0.1

Proportion of homeowners who are not insured against earthquake, q = 1 - 0.1

q = 0.9

Probability distribution of x,

$P(X = r) = ^nC_r *p^r q^{n-r} \\\\P(X= 0) =(^4C_0 *p^1 q^4 )\\P(X=0) = (^4C_0 *0.1^0 0.9^4 ) = 0.656\\P(X= 1)= (^4C_1 *p^1 q^3 )\\P(X=1) = (^4C_1 *0.1^1 0.9^3 ) = 0.2916\\P(X= 2)=( ^4C_2 *p^2 q^2) \\P(X=2) = (^4C_2 *0.1^2 0.9^2 ) = 0.0486\\P(X= 3) = (^4C_3 *p^3 q^3) \\ P(X=3) = (^4C_3 *0.1^3 0.9^1 ) = 0.0036\\P(X= 4) = (^4C_4 *p^4 q^0 )\\ P(X=4) =(^4C_4 *0.1^4 0.9^0 ) = 0.0001$

5 0

3 years ago