Answer:
The confidence Interval = (0.329, 0.391)
Step-by-step explanation:
Formula for the Confidence Interval for proportion =
p ± z × √p(1 - p)/n
where
p = x/n
From the question
n = 900 people
x = 36% of 900 people
= 36/100 × 900
= 324
z = z score of 95% confidence Interval
z = 1.98
p = x/n
= 324/900
= 0.36
Confidence Interval = p ± z × √p(1 - p)/n
= 0.36 ± 1.96 × √0.36 (1 - 0.36)/900
= 0.36 ± 1.96 ×√0.36 (0.64)/900
= 0.36 ± 1.96 × √0.000256
= 0.36 ± 1.96 × 0.016
= 0.36 ± 0.03136
Confidence Interval = 0.36 ± 0.03136
= 0.36 - 0.03136
= 0.32864
Approximately to 3 decimal places = 0.329
= 0.36 + 0.03136
= 0.39136
Approximately to 3 decimal places = 0.391
Therefore, the 95% confidence interval for the population proportion of people who believe the governor broke campaign financing laws = (0.329, 0.391)
Use a proportion. 7/10 = x/25. Multiply 10 by 2.5 to get 25. Similarly, multiply 7 by 2.5 to get 17.5. 17 1/2 pages.
so, as you can see above, the common ratio r = 1/2, now, what term is +4 anyway?
so is the 8th term, then, let's find the Sum of the first 8 terms.
![\bf S_8=512\left[ \cfrac{1-\left( \frac{1}{2} \right)^8}{1-\frac{1}{2}} \right]\implies S_8=512\left(\cfrac{1-\frac{1}{256}}{\frac{1}{2}} \right)\implies S_8=512\left(\cfrac{\frac{255}{256}}{\frac{1}{2}} \right)\\\\\\S_8=512\cdot \cfrac{255}{128}\implies S_8=1020](https://tex.z-dn.net/?f=%20%5Cbf%20S_8%3D512%5Cleft%5B%20%5Ccfrac%7B1-%5Cleft%28%20%5Cfrac%7B1%7D%7B2%7D%20%5Cright%29%5E8%7D%7B1-%5Cfrac%7B1%7D%7B2%7D%7D%20%5Cright%5D%5Cimplies%20S_8%3D512%5Cleft%28%5Ccfrac%7B1-%5Cfrac%7B1%7D%7B256%7D%7D%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%20%5Cright%29%5Cimplies%20S_8%3D512%5Cleft%28%5Ccfrac%7B%5Cfrac%7B255%7D%7B256%7D%7D%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%20%5Cright%29%5C%5C%5C%5C%5C%5CS_8%3D512%5Ccdot%20%5Ccfrac%7B255%7D%7B128%7D%5Cimplies%20S_8%3D1020%20)
