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3 years ago

Need help thanks I'll mark brainliest

Mathematics

1 answer:

sukhopar [10]3 years ago

8 0

Answer:

m∠ACD = 40°

Step-by-step explanation:

(4x + 2) + (6x - 12) = 8x,

10x - 10 = 8x,

2x = 10,

x = 5

8(5) = 40°

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blagie [28]

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Step-by-step explanation:

If they both go down from 3 then it is 3 and then -infinity.

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3 years ago

What is the percent of the discount for a $60 item that sells for $45?

goblinko [34]

Answer:

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Step-by-step explanation:

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3 years ago

I really need the help with this multiple choice question for geometry.

prisoha [69]

Answer:

A. 50°

Step-by-step explanation:

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2 years ago

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Bas_tet [7]

Answer:

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Step-by-step explanation:

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3 0

3 years ago

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astra-53 [7]

Answer:

$3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}$

Step-by-step explanation:

The period of the functions $y=a\cos(bx+c)$ , $y=a\sin(bx+c)$ , $y=a\sec (bx+c)$ or $y=a\csc(bx+c)$ can be calculated as

$T=\dfrac{2\pi}{b}$

The period of the functions $y=a\tan(bx+c)$ or $y=a\cot(bx+c)$ can be calculated as

$T=\dfrac{\pi}{b}$

A. The period of the function $y=-3\tan 3x$ is

$T=\dfrac{\pi}{3}$

B. The period of the function $y=6\sin 3x$ is

$T=\dfrac{2\pi}{3}$

C. The period of the function $y=-4\cot \dfrac{x}{4}$ is

$T=\dfrac{\pi}{\frac{1}{4}}=4\pi$

D. The period of the function $y=2\cos \dfrac{2x}{3}$ is

$T=\dfrac{2\pi}{\frac{2}{3}}=3\pi$

E. The period of the function $y=-\dfrac{2}{3}\sec \dfrac{x}{5}$ is

$T=\dfrac{2\pi}{\frac{1}{5}}=10\pi$

5 0

3 years ago