3 years ago

Need help thanks I'll mark brainliest

Mathematics

1 answer:

sukhopar [10]3 years ago

8 0

Answer:

m∠ACD = 40°

Step-by-step explanation:

(4x + 2) + (6x - 12) = 8x,

10x - 10 = 8x,

2x = 10,

x = 5

8(5) = 40°

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9× 3 1/2= Which choice is the most reasonable answer?

icang [17]

Answer:

31.5 or 63/2

Step-by-step explanation:

to do this, first you need to transform the mixed number (3 1/2) into an improper fraction, to get 7/2.

then you just multiply 9 by 7/2

9/1 (7/2)

63/2 = 31.5

both of the answers in bold are correct

8 0

3 years ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

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4 years ago

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Arada [10]

Answer:6t

Step-by-step explanation:

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3 years ago

3 1/2 divided by 3/4

Arisa [49]

4.666. Good luck!!!!!

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