Answer:
b = - 5
Step-by-step explanation:
(k + a )(k + x) + 1 = k^2 + kx + ak + ax + 1
I think the way to solve this is to worry about the 36
k^s + 1 + ak should equal 36
We know that a = 2
k^2 + 1 + 2k = 36
k^2 + 2k + 1 - 36 = 0
k^2 + 2k - 35 = 0
(k + 7)(k - 5) = 0
k = -7 is the only acceptable answer. It is given that K < 0.
bx = kx + ax
b = k + a
b = - 7 + 2
b = - 5
The scale factor of dilation is 1/2 or

because the number of rectangle one is multiplied by 1/2 to make rectangle 2
good luck
Answer:
3(x - 5)(x + 1).
Step-by-step explanation:
3x^2 - 12x - 15
Dividing through by 3:
= 3(x^2 - 4x - 5)
We need 2 numbers whose sum is -4 and whose product = -5. That is -5 and +1 , so the factors are:
3(x - 5)(x + 1).
The functions which are even are symmetric to y-axis. By even functions, it means that f(x) = f(x) for all the domain values. Thus even functions for example, x^2, 1+x^2, cosx, x^4 all follow the conditions i.e. f(x) = f(x) and thus they are symmterical to y-axis.
Both numerator and denominator are a sum of 51 terms, counted skipping 4s (numerator) and 2s (numerator).
So, you have

Use the linearity of sum to rewrite this as

So, as you can see, the numerator is exactly twice the numerator: you can cancel out the sum and you have
